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Sonja [21]
3 years ago
8

The admission fee at an amusement park is $1.50 for children and $4.00 for adults. on a certain day, 2,700 people entered the pa

rk, and the admission fees that were collected totaled $5,800. how many children and how many adults were admitted?
Mathematics
1 answer:
polet [3.4K]3 years ago
4 0
X=children y=adults
5800=1.5x+4y
2700=x+y

First, solve the second equation for y
y=2700-x
Second, take the equasion that was just solved a substitute it in for y in the first equation
5800=1.5x+4(2700-x)
diatribute the 4 within the parenthesis
5800=1.5x+10800-4x
combine like terms
5800=-2.5x+10800
subtract 10800
-5000=-2.5x
divide by -2.5
2000=x

Take the value for x and place it in the second equation(beginning)
2700=x+y
2700=2000+y
subtract 2000
700=y

There were 2000 children and 700 adults admitted.
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Hi there!


Looks like a lot of work is going on here.


Let's start by solving this equation for the x.


5x + 20y = 4


Step 1) Add -20y to both sides.


5x + 20y + - 20y = 4 - 20y 5x = -20y + 4


Step 2) Divide both sides by 5.


\frac{5x}{5}  = \frac{-20y + 4}{5}


x = -4y +  \frac{4}{5}


Final Answer:


x = -4y +  \frac{4}{5}


Now, let's solve for y.


Step 1) Add -5x to both sides.


5x + 20y + - 5x = 4 + - 5x 20y = -5x + 4


Step 2) Divide both sides by 20.


\frac{20y}{20} =  \frac{-5x + 4}{20}


y =  \frac{-1}{4} x +  \frac{1}{5}


Final Answer:


y =  \frac{-1}{4} x +  \frac{1}{5}


Hope this helps! :D


Hint - When you have two variables in an equation, and you want to solve for one, the other will end up in your answer. :)

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