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Sonja [21]
3 years ago
8

The admission fee at an amusement park is $1.50 for children and $4.00 for adults. on a certain day, 2,700 people entered the pa

rk, and the admission fees that were collected totaled $5,800. how many children and how many adults were admitted?
Mathematics
1 answer:
polet [3.4K]3 years ago
4 0
X=children y=adults
5800=1.5x+4y
2700=x+y

First, solve the second equation for y
y=2700-x
Second, take the equasion that was just solved a substitute it in for y in the first equation
5800=1.5x+4(2700-x)
diatribute the 4 within the parenthesis
5800=1.5x+10800-4x
combine like terms
5800=-2.5x+10800
subtract 10800
-5000=-2.5x
divide by -2.5
2000=x

Take the value for x and place it in the second equation(beginning)
2700=x+y
2700=2000+y
subtract 2000
700=y

There were 2000 children and 700 adults admitted.
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y = x - 16

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  2. Distribute 5:                                                                                                     5x - 80 = 2x - 56
  3. [Subtraction Property of Equality] Subtract 2x on both sides:                     3x - 80 = -56
  4. [Addition Property of Equality] Add 80 on both sides:                                3x = 24
  5. [Division Property of Equality] Divide 3 on both sides:                                x = 8

<u>Step 3: Solve for </u><em><u>y</u></em>

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  3. Subtract:                                                                                                          y = -8
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