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Sonja [21]
3 years ago
8

The admission fee at an amusement park is $1.50 for children and $4.00 for adults. on a certain day, 2,700 people entered the pa

rk, and the admission fees that were collected totaled $5,800. how many children and how many adults were admitted?
Mathematics
1 answer:
polet [3.4K]3 years ago
4 0
X=children y=adults
5800=1.5x+4y
2700=x+y

First, solve the second equation for y
y=2700-x
Second, take the equasion that was just solved a substitute it in for y in the first equation
5800=1.5x+4(2700-x)
diatribute the 4 within the parenthesis
5800=1.5x+10800-4x
combine like terms
5800=-2.5x+10800
subtract 10800
-5000=-2.5x
divide by -2.5
2000=x

Take the value for x and place it in the second equation(beginning)
2700=x+y
2700=2000+y
subtract 2000
700=y

There were 2000 children and 700 adults admitted.
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2 years ago
2( 10 - a^2 ) + 7a If ( a = 4 )Evaluate each expression
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Solution:

Given:

2(10-a^2)+7a

when a = 4, substitute for a in the expression;

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Therefore, if (a = 4), then

2(10-a^2)+7a=16

Hence, the answer is 16.

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2 years ago
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Answer:

Step-by-step explanation:

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MrRa [10]
Answer is:
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3 years ago
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