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2 years ago

Find the value of x (URGENT/GIVING BRAINLIEST)

Mathematics

2 answers:

Aleks04 [339]2 years ago

8 0

Answer:

x = 10°

Step-by-step explanation:

5x° + 40° = 90°

5x° = 90°-40°

5x°=50°

x°= 50°/5

x = <u>10°</u>

natta225 [31]2 years ago

7 0

Answer:

B)10

Step-by-step explanation:

Because this is a right angle(indicated by the red box) the total measure should be 90°.

And based on that we say 5X +40=90

Subtract 40 from both sides to get 5x=50

And then divide both sides by 5 to get x=10

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A number is picked randomly in the range [0,7]. What is the probability that the number picked is between 3 and 5? What is the p

emmasim [6.3K]

Answer:

(1) 0.125

(2) 0.125

Step-by-step explanation:

The total number of possible outcomes is:

N = 8

(1)

Compute the probability that the number picked is between 3 and 5 as follows:

Number of Favorable outcomes = 1

The probability is:

P (Number picked is between 3 and 5) = 1/8 = 0.125

Thus, the probability that the number picked is between 3 and 5 is 0.125.

(2)

The number usually picked appears to be in in the range [3,5], i.e. the numbers could be, {3, 4 or 5}.

Number of Favorable outcomes = n (Number < 4 and within [3, 5]) = 1

P (less than 4 ∩ within [3, 5]) = 1/8 = 0.125

Thus, the probability that the number picked is less than 4 knowing that the number usually picked appears to be in in the range [3,5] is 0.125.

4 0

3 years ago

Use the following triangle to find Sec theta.

makkiz [27]

Answer:

$\frac{\sqrt{41}}{4}$

Step-by-step explanation:

sec(theta) is defined as: $sec(\theta)=\frac{1}{cos(\theta)} = \frac{hypotenuse}{adjacent}$

In the diagram you provided the hypotenuse of the triangle is sqrt(41) and the opposite side is 5, using these two sides, we can solve for the adjacent side by using the Pythagorean Theorem: $a^2+b^2=c^2$

So this gives us the equation where a=adjacent side:

$a^2+5^2=\sqrt{41}^2$

$a^2+25=41$

Subtract 25 from both sides

$a^2=16$

Take the square root of both sides

$a=4$

So now plug this into the definition of sec(theta) and you get: $\frac{\sqrt{41}}{4}$ . This is in most simplified form since 41, has no factors besides 41 and 1.

7 0

2 years ago

I really need help!!!

Zigmanuir [339]

Answer:

$Pr = 6.67\%$