Answer:
The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. [beep] A single lap should be completed each time you hear this sound. [ding] Remember to run in a straight line, and run as long as possible. The second time you fail to complete a lap before the sound, your test is over.
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Answer:
6.2 moles of K2CO3 can be converted to 856.8741 grams.
<span>A colloid can be detected by using the Tyndall effect. The correct option among all the options that are given in the question is the second option. The other choices are incorrect and can be easily neglected. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span>
<span>Answer:
Anthracene is a solid polycyclic aromatic hydrocarbon (PAH) which has the formula as C14H10, consisting of three fused benzene rings. It is a component of coal tar. Anthracene is used in the production of the red dye alizarin and other dyes.</span>
Answer : The specific heat of the substance is 0.0936 J/g °C
Explanation :
The amount of heat Q can be calculated using following formula.

Where Q is the amount of heat required = 300 J
m is the mass of the substance = 267 g
ΔT is the change in temperature = 12°C
C is the specific heat of the substance.
We want to solve for C, so the equation for Q is modified as follows.

Let us plug in the values in above equation.


C = 0.0936 J/g °C
The specific heat of the substance is 0.0936 J/g°C