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zaharov [31]
3 years ago
12

When table salt (NaCl) is added to water, it lowers the freezing point is more salt is added, the freezing point decreases even

Chemistry
1 answer:
AleksAgata [21]3 years ago
7 0
The answer to the question is B
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HELP PLS !!!!! NO LINKS
Nuetrik [128]

Answer:

<h2><em><u>Option a</u></em></h2><h2><em><u>Weathering</u></em></h2>

Explanation:

<h3><em>Weathering is a term which describes the general process by which rocks are broken down at the Earth's surface into such things as sediments, clays, soils and substances that are dissolved in water. </em></h3>

<u><em>As weathered products are carried away, fresh rocks are exposed to further </em><em>we</em><em>athering</em><em>.</em></u>

8 0
3 years ago
Read 2 more answers
How many moles of AlCl3 are in 2.25L of a 0.15 molar solution?
Darya [45]

Answer:

Option C. 0.34 moles

Explanation:

Data obtained from the question include:

Molarity = 0.15M

Volume = 2.25L

Mole =

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.15 x 2.25

Mole = 0.34mole

The number of mole of AlCl3 present in the solution is 0.34mole.

5 0
3 years ago
Builders and dentists must store plaster of Paris,
eimsori [14]

Answer:

547 L of water vapour

Explanation:

Equation of reaction: 2[CaSO4.2H20] + Heat ---> 2[CaSO4.½H2O] + 3H20

From the equation of reaction above, 2 moles of gypsum when heated produces 2 moles of plaster of Paris and 3 moles of water vapour.

Molar mass of gypsum = 172 g/mol

Molar mass of H2O = 18 g/mol

Therefore, 2 * 172 g of gypsum produces 3 * 18 g of water vapour

i.e. 344 g of gypsum produces 54 g of H2O

2 Kg(2000 g) of gypsum will produce (54 * 2000)/344 g of water vapour = 313.95 of water vapour.

Volume of water vapour produced = mass/density

Volume of water vapour = 313.95 g/ 0.574 g/L = 547 L of water vapour

Therefore 547 L of water vapour are produced

3 0
3 years ago
Suppose hydrochloric acid reacts with potassium sulfite yielding water, sulfur dioxide, and potassium chloride. Suppose 4 moles
anzhelika [568]

Answer:

128 grams of sulfur dioxide are produced.

Explanation:

2HCl+K_2SO_3\rightarrow SO_2+2KCl+H_2O

Moles of HCl = 4 moles

According to reaction, 2 moles of HCl gives 1 mole of sulfur dioxide gas.

Then 4 moles of HCl will give:

\frac{1}{2}\times 4 moles=2 moles of sulfur dioxide gas.

Mass of sulfur dioxide gas = 2 mol × 64 g/mol = 128 g

128 grams of sulfur dioxide are produced.

4 0
3 years ago
Gaseous hydrogen and oxygen can be prepared in the laboratory from the decomposition of gaseous water. The equation for the reac
nata0808 [166]

Answer:

m_{O_2}=87.2gO_2

Explanation:

Hello.

In this case, given the chemical reaction, we can compute the grams of oxygen by using the 98.2 g of water via the 2:1 mole ratio between them, the molar mass of water that is 18.02 g/mol, the molar mass of gaseous oxygen that is 32.00 g/mol and the following stoichiometric procedure relating the given information:

m_{O_2}=98.2gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molO_2}{2molH_2O}*\frac{32.00gO_2}{1molO_2}   \\\\m_{O_2}=87.2gO_2

In which the result is displayed with three significant figures because the given mass of water 98.2 g, has three significant figures too.

Best regards!

6 0
3 years ago
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