All categories

3 years ago

In which of the following quadrilaterals are consecutive and opposite angles always congruent?

2 answers:

6 0

All the angles are congruent in square and rectangle, rhombus has consecutive angles so we can say that all of them have consecutive angles congruent except the parallelogram.

Mama L [17]3 years ago

6 0

The correct answers are A. Rectangle and D. Square

Parallelograms and Rhombuses have supplementary angles

You might be interested in

Muskaan had 157 dollars to spend on 6 books. After buying the she had 13 dollars. How much did each book cost?

nirvana33 [79]

Answer:

the cost of each book = $24

Step-by-step explanation:

(if all the books have the same price)

Let x be the price of one book

“She had $157 and After buying 6 books ,she was left with 13$“ means

“157 = 6x + 13”

now we have an equation to solve :

157 = 6x + 13

⇔ 157 - 13 = 6x

⇔ 144 = 6x

⇔ 24 = x

5 0

2 years ago

Please please help!!

shepuryov [24]

Answer:

$\large\boxed{x=0\ and\ x=\pi}$

Step-by-step explanation:

$\tan^2x\sec^2x+2\sec^2x-\tan^2x=2\\\\\text{Use}\ \tan x=\dfrac{\sin x}{\cos x},\ \sec x=\dfrac{1}{\cos x}:\\\\\left(\dfrac{\sin x}{\cos x}\right)^2\left(\dfrac{1}{\cos x}\right)^2+2\left(\dfrac{1}{\cos x}\right)^2-\left(\dfrac{\sin x}{\cos x}\right)^2=2\\\\\left(\dfrac{\sin^2x}{\cos^2x}\right)\left(\dfrac{1}{\cos^2x}\right)+\dfrac{2}{\cos^2x}-\dfrac{\sin^2x}{\cos^2x}=2$

$\dfrac{\sin^2x}{(\cos^2x)^2}+\dfrac{2-\sin^2x}{\cos^2x}=2\\\\\text{Use}\ \sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-(1-\cos^2x)}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-1+\cos^2x}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{1+\cos^2x}{\cos^2x}=2$

$\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{(1+\cos^2x)(\cos^2x)}{(\cos^2x)^2}=2\qquad\text{Use the distributive property}\\\\\dfrac{1-\cos^2x+\cos^2x+\cos^4x}{\cos^4x}=2\\\\\dfrac{1+\cos^4x}{\cos^4x}=2\qquad\text{multiply both sides by}\ \cos^4x\neq0\\\\1+\cos^4x=2\cos^4x\qquad\text{subtract}\ \cos^4x\ \text{from both sides}\\\\1=\cos^4x\iff \cos x=\pm\sqrt1\to\cos x=\pm1\\\\ x=k\pi\ for\ k\in\mathbb{Z}\\\\\text{On the interval}\ 0\leq x$

4 0

3 years ago

Helen had to read 148 pages of her science textbook in the 4 days remaining before an exam. If she reads the same number of page

iragen [17]

Answer:

b)37

Step-by-step explanation:

8 0

3 years ago

Which of the following expresses the possible number of positive real solutions for the polynomial equation shown below?

sesenic [268]

Answer: D. Two or zero

Step-by-step explanation: x=-7/6+-1/6√385

There isn't an exact place you could really solve this number, regardless of the way you break it down

5 0

3 years ago

Please help me finish these for summer school :)

ValentinkaMS [17]

13.45 will be the answer

since we are finding the hypotenuse, the formula is a^2 + b^2 = c^2

this will then be 10^2 + 9^2 = c^2

181=c^2

c=13.45 :)

5 0

3 years ago

Read 2 more answers