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3 years ago

In which of the following quadrilaterals are consecutive and opposite angles always congruent?

2 answers:

6 0

All the angles are congruent in square and rectangle, rhombus has consecutive angles so we can say that all of them have consecutive angles congruent except the parallelogram.

Mama L [17]3 years ago

6 0

The correct answers are A. Rectangle and D. Square

Parallelograms and Rhombuses have supplementary angles

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Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

vazorg [7]

the scale is x4

because 10x4=40

11x4=44

18x4=72

you multiply by 4 on all of them

6 0

3 years ago

Read 2 more answers

the area of a rectangle is 188 meters squared .find the length of the rectangle if the width is 4 meters, using the formula A=lw

sergiy2304 [10]

A = LW
A = 188
W = 4

188 = 4L
188/4 = L
47 = L....so the length is 47 meters

5 0

3 years ago

Juan has 12 pencils. two-thirds of these pencils are sharpned which model represents the number of sharpend pencils juan has?

Oduvanchick [21]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The profit from a business is

GuDViN [60]

First of all we will understand the question!!

The question is saying that you are given a function and you have to find the value of x which will give the maximum profit... Lets solve it by finding the extrema using the vertex

 $\rm \: p(x) = - 5 {x}^{2} + 30x + 8$ 

Identify the coefficients a and b of the quadratic function

 $\rm \: p(x) = { - 5x}^{2} + 30x + 8 \\ \rm \: a = - 5 \: and \: b \: = 30$ 

Since a<0, the function has the maximum value at x, calculated by substituting a and b into x=-b/2a

$\rm \: x = \frac{30}{ 2 \times (- 5)}$

Solve the equation for x

$\rm \: x = 3$

The maximum of the quadratic function is at x=3

3 0

2 years ago

Find the number of integral solutions of x+y +z = 12, where −3 ≤ x ≤ 4, 2 ≤ y ≤ 11, and z ≥ 3.

SashulF [63]

There are 59 integer solutions

Such questions are best solved by writing cases and calculating the total number of cases. So beginning with

1) x = -3. The possible combinations are as follows:-

-3 2 13

-3 3 12

-3 4 11

-3 5 10

-3 6 9

-3 7 8

-3 8 7

-3 9 6

-3 10 5

-3 11 4

10 combinations

2) x = -2

-2 2 12

through

-2 11 3

10 combinations

3) x = -1

-1 2 11

through

-1 10 3

9 combinations

4) x = 0

0 2 10

through

0 9 3

8 combinations

as we can see from the pattern at x =1 we get 7 combinations, at x =2 we get 6 combinations, at x=3 we get 5 combinations and at x =4 we get 5 combinations.

Thus total number of combinations 4+5+6+7+8+9+10+10 = 59 integer solution.

Learn more about combinations here :

brainly.com/question/13387529

#SPJ1

5 0

2 years ago