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2 years ago

The probability that it will snow on Friday is 70%, and the probability that it will snow on Saturday is 50%.

1 answer:

4 0

P(Snow Friday) = 0.7, P(No Snow Friday) = 1-0.7 = 0.3
P(Snow Saturday) = 0.3, P(No snow Saturday) = 1-0.3 = 0.7

Then,
P(Snow Friday) and P(Snow Saturday) = 0.7*0.3 = 0.21

P(No snow Friday) and P(No snow Saturday) = 0.3*0.7 = 0.21

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Consider a circle (radius R) to be made up of many concentric rings of radius r and thickness dr. Find the area, dA, of one of t

Zanzabum

Answer:

Step-by-step explanation:

<h3>Please refer to the attachment for explanation.</h3>

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3 years ago

Pls answer it right ill brainliest u

Rufina [12.5K]

P=10h is the right one i believe

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2 years ago

Read 2 more answers

Circle O has a center at (-2, 10) and a

allsm [11]

Answer:

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

$distance = \sqrt{(y1 - y2)^{2} + {(x1 - x2)}^{2} }$

A. Distance between 2 points

$= \sqrt{ {(10 + 5)}^{2} + ( - 2 + 6)^{2} } \\ = \sqrt{15 ^{2} + {4}^{2}} \\ = \sqrt{241} \\ = 15.524 \: units$

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2} } \\ = \sqrt{ {6}^{2} } \\ = 6 \: units$

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + {( - 2 - 6)}^{2} } \\ = \sqrt{ {6}^{2} + ( - 8)^{2} } \\ = \sqrt{100} \\ = 10 \: units$

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

$= \sqrt{ {(10 - 8)}^{2} + {( - 2 - 8)}^{2} } \\ = \sqrt{2^{2} + ( - 10)^{2} } \\ = \sqrt{104} \\ = 10.198 \: units$

(to 5 s.f.)

Point D also lies outside Circle O.

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3 years ago

If half of Allen's test score plus 8 equals 50. What did Allen score on his test? Let s, represent Allens score.

dmitriy555 [2]

50-8=42(half of his score)
42*2=84(whole score)
s=84

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2 years ago

PROBLEM SOLVING: Xavier made 25 pounds of roasted almonds for a fair. He has 3 1/2 pounds left at the end of the fair. How many

Goshia [24]

To solve this problem, you'll need to subtract 25 (total quantity of roasted almonds) by the remaining variable of roasted almonds (3 1/2 lbs.), resultant towards finding how many pounds of roasted almonds Xavier had sold; Xavier had sold 21 1/2 pounds of almonds.

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2 years ago