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aleksandrvk [35]
3 years ago
10

Two unidentified flying discs are detected by a receiver. The angle of elevation from the receiver to each disc is 39.48 degree.

The discs are hovering at a direct distance of 826m and 1.296km from the receiver. Find the difference in height between the two unidentified flying discs, to the nearest meter.
Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

The answer is "298.83 m"

Step-by-step explanation:

Its gap from its transmitter from each disc comprises of 2 triangles. Its horizontal segment via disc to vertical, and longitudinal segment. Disk height, h, is parallel to a horizontal disc Wink including its line across recipient to disc or horizontal 39. 48^{\circ}

\to 39. 48^{\circ}  = \frac{h_1}{826 \ m}\\\\   \to 826\ m (\ sin 39. 48^{\circ} ) = h_1\\\\ \to 525.18 = h_1\\\\

if:

\to \sin 39. 48^{\circ} = \frac{h_2}{1.296 \ km}\\\\ \to  \sin 39. 48^{\circ} (1296 \ m) = h_2\\\\  \to  824.01 = h_2\\\\\to                        h_2  - h_1 = 824.01 - 525.18\\\\

                  = 298.83 \ m

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