Question

Two unidentified flying discs are detected by a receiver. The angle of elevation from the receiver to each disc is 39.48 degree. The discs are hovering at a direct distance of 826m and 1.296km from the receiver. Find the difference in height between the two unidentified flying discs, to the nearest meter.

Answer 1

Answer:

The answer is "298.83 m"

Step-by-step explanation:

Its gap from its transmitter from each disc comprises of 2 triangles. Its horizontal segment via disc to vertical, and longitudinal segment. Disk height, h, is parallel to a horizontal disc Wink including its line across recipient to disc or horizontal 39. 48^{\circ}

$\to 39. 48^{\circ} = \frac{h_1}{826 \ m}\\\\ \to 826\ m (\ sin 39. 48^{\circ} ) = h_1\\\\ \to 525.18 = h_1$

if:

$\to \sin 39. 48^{\circ} = \frac{h_2}{1.296 \ km}\\\\ \to \sin 39. 48^{\circ} (1296 \ m) = h_2\\\\ \to 824.01 = h_2\\\\\to h_2 - h_1 = 824.01 - 525.18$

                  $= 298.83 \ m$