Answer:

Step-by-step explanation:
I am assuming that you mean (4,−9) and (8, -3).

Hope this helps.
If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Hey there!
<u>Find </u><u>f(</u><u>-</u><u>3</u><u>)</u><u> </u><u>:</u>
f(-3) = 8 ✅
f(x) = -x + 5
<em>></em><em>></em><em> </em><em>Substitute </em><em>-</em><em>3</em><em> </em><em>for </em><em>x </em><em>in </em><em>f(</em><em>x)</em><em> </em><em>:</em><em> </em>
f(-3) = -(-3) + 5
f(-3) = 3 + 5
f(-3) = 8
Therefore, your answer is f(-3) = 8
Similar question :
↣ brainly.com/question/20922457
Answer:
(-12, -12)
Step-by-step explanation:
Since the scale factor is 3, you would multiply the x-coordinate and y-coordinate by it.
-4×3=-12
Hope this helps!!