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Brilliant_brown [7]
3 years ago
14

A series of books has 30 volumes, each with 700 pages. What is the total number of pages in the series?

Mathematics
1 answer:
elena55 [62]3 years ago
7 0

Answer:

Step-by-step explanation:

Here we have to multiply to find the total...

30 volumes, then each individual book with 700 pages, therefore, the answer would be 21,000 pages

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3 years ago
Which word does NOT belong with the others? A. triangle B. circle C. oval D. sphere
Phoenix [80]

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A triangle

Step-by-step explanation:

If you slice open all of these shapes you will see a circle except the triangle.

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Convert the angle 3pi/5 radians to degrees
Artyom0805 [142]

well, we know that π is 180°, so then what is 3π/5?

\begin{array}{ccll} radians&degrees\\ \cline{1-2} \pi &180\\ \frac{3\pi }{5}&x \end{array}\implies \cfrac{\pi }{~~ \frac{3\pi }{5}~~}~~ = ~~\cfrac{180}{x}\implies \cfrac{5\pi }{3\pi }=\cfrac{180}{x} \\\\\\ \cfrac{5}{3}=\cfrac{180}{x}\implies 5x=540\implies x=\cfrac{540}{5}\implies x=108

8 0
2 years ago
A recent study reported that 29​% of the residents of a particular community lived in poverty. Suppose a random sample of 200 re
ki77a [65]

Answer:

a) The probability of having a sample of 200 people and having more than 33% of residents living in poverty is P=0.10312 or 10.3%.

b) The probability of having a sample of 200 people and having more than 24% of residents living in poverty is P=0.94091 or 94.1%.

Step-by-step explanation:

a) As the proportion for the population is μ=0.29 , we expect the porportion for the sample to be around p=0.29, <em>with 50% of chances of being higher and 50% of chances of being lower than 0.29</em>.

The probability of having a sample with 33% or more is less than 50%, because 0.33 is greater than the population proportion of 0.29.

To calculate P(p>0.33) you have to substract from the probability of having more than 29% poverty, which is 50%, the probability of having between 29% and 33%, which is not null.

We can write this as:

P(p>0.33)=P(p>0.29)-P(0.29

And we know P(0.29 is greater than zero, so P(p>0.33)[\tex] is less than 0.5 or 50%.If we want to calculate the proability of having a p>0.33 with a sample of n=200, and assuming we can apply the central limit theorem (CLT), we have to calculate first the z-value:[tex]z=\frac{p-\bar{p}}{\sigma} =\frac{p-\bar{p}}{\sqrt{\frac{\bar{p}*(1-\bar{p})}{n}}} \\\\z=\frac{0.33-0.29}{\sqrt{\frac{0.29*(1-0.29)}{200}}}=\frac{0.04}{0.032}=1.246

With this value of z, we can look up the probability of having p>0.33

P(p>0.33)=P(z>1.246)=0.10312

b) The probability of having a sample with 24% or more is more than 50%, because 0.24 is smaller than the population proportion of 0.29, so we add the 50% chances of being above the mean to the proability of having between 0.24 and 0.29 of poverty proportion, which is greater than zero.

If we want to calculate the proability of having a p>0.24 with a sample of n=200, and assuming we can apply the central limit theorem (CLT), we have to calculate first the z-value:

z=\frac{p-\bar{p}}{\sigma} =\frac{p-\bar{p}}{\sqrt{\frac{\bar{p}*(1-\bar{p})}{n}}} \\\\z=\frac{0.24-0.29}{\sqrt{\frac{0.29*(1-0.29)}{200}}}=\frac{-0.05}{0.032}=-1.5625

With this value of z, we can look up the probability of having p>0.24

P(p>0.24)=P(z>-1.5625)=0.94091

8 0
3 years ago
Find the 1000th term of the sequence below
Andre45 [30]

Answer:

A. 7017

Step-by-step explanation:

common difference is 7

first term of the sequence is 24

by explicit formula a1 + ( n- 1)*d

24 + (1000-1)*7

24+999*7

24+6993

7017

4 0
4 years ago
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