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3 years ago

What is 589 + 983 math question?

Mathematics

2 answers:

zepelin [54]3 years ago

6 0

1 1
589
+ 983
_____
1572

zhenek [66]3 years ago

3 0

The answer is 1,572 please give this a THANKS and also the BRAINIEST ANSWER/CROWN! :) :D

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Two lines, a and b, are represented by the equations given below:

ElenaW [278]

An system of equations is only true if it satisfies both equations

<h2>c) (-4, -8), because the point satisfies both equations </h2>

8 0

3 years ago

Read 2 more answers

Help! Willing to give brainliest

vovikov84 [41]

Answer : 4th option

A equation is given to us and we need to find out its graph from the options . The given equation is ,

→ y = -2x + 1

Comparing this equation to the slope intercept form of the line which is y = mx + c , where m is the slope and c is y intercept. We have ,

m = -2
c = 1

So the equation of the line will cut y axis at (0,1) and will have a negative slope .

Since the slope is negative , it will make an obtuse angle in anti clockwise direction with the x axis .

And the graph which satisfies the above conditions is in 4th option .

Hence the correct answer is 4th option .

I hope this helps.

4 0

2 years ago

What is the equation of the line that passes through the point (-2, 7) and has a slope of zero

lorasvet [3.4K]

Answer:

y = 7 is the equation of the line that passes through the point ( -2, 7 ) and has a slope of zero.

Step-by-step explanation:

Given:

Let,

A ≡ ( x1 , y1 ) ≡ ( -2, 7 )

Slope = m = 0

To Find :

Equation of Line:

Solution:

Formula for , equation of a line passing through a point ( x1 , y1 ) and having a slope m is given by

$(y - y_{1})=m(x-x_{1})$

Now substituting the values of x1 = -2 and y1 = 7 and slope m = 0 we get,

$y-7=0\times(x--2) \\y-7=0\times (x+2)\\y-7=0\\\therefore y=7$

Which is the required equation of a line passing through the point ( -2, 7 ) and slope zero

6 0

3 years ago

A surveyor on one side of a river wishes to find the distance between points a and b on the opposite side of the river. On her s

Tcecarenko [31]

Question not clear, i think it's incomplete else sorry

5 0

3 years ago

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago