El numero 38 es par o impar El numero 35 es par o impar?
2 answers:
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X^a/b is ![\sqrt[b]{x^a}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bb%5D%7Bx%5Ea%7D%20)
. The way I memorise that is x^1/3 is the cubic root of x. Do you get it? In that case, x is raised to a power of 1 and the cubic root is practically has a power of 3.
In your example,
![\sqrt[ \frac{3}{2} ]{16 x^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B%20%5Cfrac%7B3%7D%7B2%7D%20%5D%7B16%20x%5E4%7D)
is practically square rooting each term then cubing them individually. Remember when square-rooting any index you halve it. I'll elaborate:
= 
= 4
Then cube each,
= 64
and
= 
As for the 2nd part: you must use the rules of indices.
So breaking the question up:
3 * 3 = 9
stays as is since the 2nd term does not contain x
now:
This makes your final answer look like this:
I hope that helped and good luck in your test!
In your example,
Then cube each,
and
As for the 2nd part: you must use the rules of indices.
So breaking the question up:
3 * 3 = 9
now:
This makes your final answer look like this:
I hope that helped and good luck in your test!
Answer:
A = m²
Step-by-step explanation:
Given that a square has a perimeter of (2x - 48),
Each side of the perimeter must be: (because a square has 4 sides)
We need to determine the side of each perimeter:
s =
Factor out 2 from the numerator:
s =
Then, cancel out 2 and 4 from the fraction, leaving 2 in the denominator:
s = ← <em><u>This represents the side of a square</u></em>
Therefore, the area of a square is:
A = side (s)²
A = m²