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natita [175]
4 years ago
15

The areas of two equilateral triangles are 27 yd2 and 75 yd2. Find the ratio of their perimeters.

Mathematics
2 answers:
Cloud [144]4 years ago
8 0
If the areas of two equilateral triangles are 27 yd² and 75 yd², then the ratio of these areas is 27/75 = 9/25 

If the ratios of the areas are 9:25, then their similarity ratio and the ratio of their perimeters is √9:√35 = 3:5. 

3 : 5; 3 : 5 <==ANSWER 
Dominik [7]4 years ago
7 0

Answer:

3:5

Step-by-step explanation:

The areas of two equilateral  triangles are 27 square yards and 75 square yards.

The area of an equilateral triangle with sides length 'a' is given by

\frac{\sqrt3}{4}a^2

Therefore, we have

\frac{\frac{\sqrt3}{4}a_1^2}{\frac{\sqrt3}{4}a_2^2}=\frac{27}{75}\\\\\frac{a_1}{a_2}=\frac{3\sqrt3}{5\sqrt3}

Now, multiply and divide both sides by 3

\frac{3a_1}{3a_2}=\frac{9\sqrt3}{15\sqrt3}\\\\\frac{P_1}{P_2}=\frac{9}{15}\\\\\frac{P_1}{P_2}=\frac{3}{5}

Hence, the ratio of perimeters of the given two equilateral triangles is 3:5

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Point A has coordinates (3,4). After a translation 4 units left, a reflection across the x-axis, and a translation 2 units down,
jeka94

Answer:

The coordinates of the image of point A are (-1, -6)

Step-by-step explanation:

Let us revise the rule of translation to the left, down, and reflection across the x-axis

  • If the point (x, y) translated horizontally to the left by h units then its image is (x - h, y) ⇒ T (x, y) → (x - h, y)
  • If the point (x, y) translated vertically down by k units then its image is (x, y - k) ⇒ T (x, y) → (x, y - k)
  • If the point (x, y) reflected across the x-axis, then its image is (x, -y), the rule of reflection is rx-axis (x, y) → (x, -y)

∵ The coordinates of point A are (3, 4)

∵ It is translated 4 units left

∴ h = 4

→ By using the 1st rule above

∴ Its image is (3 - 4, 4)

∴ Its image is (-1, 4)

∵ Its is reflected across the x-axis

→ By using the 3rd rule above change the sign of its y-coordinate

∴ The new image is (-1, -4)

∵ It is translated 2 units down

∴ k = 2

→ By using the 2nd rule above

∴ The final image is (-1, -4 - 2)

∴ The final image is (-1, -6)

∴ The coordinates of the image of point A are (-1, -6).

6 0
3 years ago
The perimeter of the patio is 64 feet. The width of the patio is (x+2) feet and the length of the patio is (x+6) feet. What are
ValentinkaMS [17]

The formula for the perimeter is P = 2<em>w</em> + 2<em>l</em>, where <em>w</em> is the width and <em>l</em> is the length. It is given that the width = (x+2) and the length = (x+6). Therefore, we can make this equation:

P = 2<em>w</em> + 2<em>l</em>

64 = 2(x+2) + 2(x+6) ⇒ Distributive property

⇒ 64 = 2x + 4 + 2x + 12 ⇒ Combine like terms

⇒ 64 = 4x + 16 ⇒ Subtract 16 from both sides

⇒ 48 = 4x ⇒ Divide both sides by 4

⇒ x = 12

Then, we use x = 12 and substitute it in to find the length and width

<em>Width</em> = (x+2) = (12+2) = 14

<em>Length</em> = (x+6) = (12+6) = 18

The dimensions of the patio is <u>14 by 18</u>

5 0
3 years ago
What property of equality is used when combining like terms in an equation?
svet-max [94.6K]
The correct answer is C. Commutative Property
3 0
3 years ago
Read 2 more answers
2 2/3 of what number is 6 1/7
borishaifa [10]

2\frac{2}{3} of 2\frac{17}{56} is 6\frac{1}{7}

Solution:

Given 2\frac{2}{3} of what number is 6\frac{1}{7}.

Let us first convert the mixed fraction into improper fraction.

$2\frac{2}{3}=\frac{(2\times3)+2}{3}=\frac{8}{3}

$6\frac{1}{7}=\frac{(6\times7)+1}{3}=\frac{43}{3}

Now, let us take the unknown number be x.

$2\frac{2}{3}\times x=6\frac{1}{7}

$\frac{8}{3}\times x=\frac{43}{7}

Do the cross multiplication.

$ x=\frac{43}{7}\times\frac{3}{8}

$ x=\frac{43\times3}{7\times8}

$ x=\frac{129}{56}

Now, again change the improper fraction into mixed fraction.

$ x=2\frac{17}{56}

Hence 2\frac{2}{3} of 2\frac{17}{56} is 6\frac{1}{7}.

6 0
3 years ago
An amount of $35,000 is borrowed for 6 years at 4.5% interest, compounded annually. if the loan is paid in full at the end of th
Vlada [557]
Answer: $45579.10 
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