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natita [175]
3 years ago
15

The areas of two equilateral triangles are 27 yd2 and 75 yd2. Find the ratio of their perimeters.

Mathematics
2 answers:
Cloud [144]3 years ago
8 0
If the areas of two equilateral triangles are 27 yd² and 75 yd², then the ratio of these areas is 27/75 = 9/25 

If the ratios of the areas are 9:25, then their similarity ratio and the ratio of their perimeters is √9:√35 = 3:5. 

3 : 5; 3 : 5 <==ANSWER 
Dominik [7]3 years ago
7 0

Answer:

3:5

Step-by-step explanation:

The areas of two equilateral  triangles are 27 square yards and 75 square yards.

The area of an equilateral triangle with sides length 'a' is given by

\frac{\sqrt3}{4}a^2

Therefore, we have

\frac{\frac{\sqrt3}{4}a_1^2}{\frac{\sqrt3}{4}a_2^2}=\frac{27}{75}\\\\\frac{a_1}{a_2}=\frac{3\sqrt3}{5\sqrt3}

Now, multiply and divide both sides by 3

\frac{3a_1}{3a_2}=\frac{9\sqrt3}{15\sqrt3}\\\\\frac{P_1}{P_2}=\frac{9}{15}\\\\\frac{P_1}{P_2}=\frac{3}{5}

Hence, the ratio of perimeters of the given two equilateral triangles is 3:5

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147.1 is what percent of 155
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Solution for what is 147.1% of 155

155/x=100/147.1
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2 years ago
Find c.
Vinvika [58]
<h3>Answer:   0.5</h3>

========================================================

Explanation:

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We don't know the value of lowercase 'a', so we'll ignore the sin(A)/a portion.

This leaves sin(B)/b

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The lowercase letters represent side lengths, while the uppercase letters are angles.

--------------------------

We have enough to apply the law of sines to solve for side c.

sin(B)/b = sin(C)/c

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Make sure your calculator is in degree mode.

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