9514 1404 393
Answer:
a) ∆RLG ~ ∆NCP; SF: 3/2 (smaller to larger)
b) no; different angles
Step-by-step explanation:
a) The triangles will be similar if their angles are congruent. The scale factor will be the ratio of any side to its corresponding side.
The third angle in ∆RLG is 180° -79° -67° = 34°. So, the two angles 34° and 67° in ∆RLG match the corresponding angles in ∆NCP. The triangles are similar by the AA postulate.
Working clockwise around each figure, the sequence of angles from lower left is 34°, 79°, 67°. So, we can write the similarity statement by naming the vertices in the same order: ∆RLG ~ ∆NCP.
The scale factor relating the second triangle to the first is ...
NC/RL = 45/30 = 3/2
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b) In order for the angles of one triangle to be congruent to the angles of the other triangle, at least one member of a list of two of the angles must match for the two triangles. Neither of the numbers 57°, 85° match either of the numbers 38°, 54°, so we know the two triangles have different angle measures. They cannot be similar.
Answer:
$6.60
Step-by-step explanation:
6.20 x 3 = 18.60
6.90 x 4 = 27.60
18.60 + 27.60 = 46.20
46.20 ÷ 7 = 6.60
Answer:
-√10,√11 , 3.30, 17/5
Step-by-step explanation:
-√10,√11 , 3.30, 17/5
17/5 is 3.4
the 10 is a negative so its the smallest
11 square root is a imiganery
Answer:
The inequality is equivalent to x(x+2)(x−3)>0 , with the additional conditions that x≠0 and x≠3 .
Since x(x+2)(x−3) only changes signs when crossing −2 , 0 and 3 , from the fact that the evaluating the polynomial at 4 yields 24 , we see that the polynomial is
positive over (3,∞)
negative over (0,3)
positive over (−2,0)
negative over (−∞,−2)
Thus the solution set for your inequality is (−2,0)∪(3,∞) .
Step-by-step explanation:
hi Rakesh here is your answer :)
#shadow
Answer:
354
Step-by-step explanation:
