Answer:
Liquid: 38.7 g x 1 ml/0.865 g = ml of liquid
Vol of solid = 80.0 ml - ml of liquid
mass of solid = vol of solid x 2.75 g/ml
(100. g)
Explanation:
you can use this as a eg for this question
The rate of Formation of Carbocation mainly depends on two factors'
1) Stability of Carbocation: The ease of formation of Carbocation mainly depends upon the ionization of substrate. If the forming carbocation id tertiary then it is more stable and hence readily formed as compared to secondary and primary.
2) Ease of detaching of Leaving Group: The more readily and easily the leaving group leaves the more readily the carbocation is formed and vice versa. In given scenario the carbocation formed is tertiary in all three cases, the difference comes in the leaving group. So, among these three substrates the one containing Iodo group will easily dissociate to form tertiary carbocation because due to its large size Iodine easily leaves the substrate, secondly Chlorine is a good leaving group compared to Fluoride. Hence the order of rate of formation of carbocation is,
R-I > R-Cl > R-F
B > C > A
Answer:
Tyrel is learning about a certain kind of metal used to make satellites. He learns that infrared light is absorbed by the metal. X-ray light is transmitted through the metal. ... Yes, light can cause the metal to get warm because light carries energy.
Answer:
Group 8 elements are inert and possess :
1. Low Boiling Points
2. High ionization energies
3. Electronegativities is very low
4. No color, odor
Explanation:
Group 8 elements are also called as Noble Gases. They are unreactive.
They have low boiling points means they remains monoatomic at room temperature. Having high ionization energy means that it is very difficult to remove an electron from its valence shell.
The Arrhenius equation is
so if we plot a graph between lnK (natural log of rate constant) and 1/T (inverse of temperature in kelvin)
The straight line equation will be
lnK = lnA - Ea/RT
Where
A = constant for a particular reaction at any temperature
R = gas constant = 8.314 J /molK
So as per this equation the slope of line will be = -Ea/R
Or
Ea = -slope X R
Ea = -(-9.20X10³X 8.314) =76.49kJ /mol
Answer: activation energy = 76.49 kJ /mol