The NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.
A spectroscopic method for observing the local magnetic fields surrounding atomic nuclei seems to be nuclear magnetic resonance spectroscopy, also referred to as magnetic resonance spectroscopy as well as NMR spectroscopy.
The identification and study of organic molecules benefit greatly from nuclear magnetic resonance (NMR) spectroscopy. This type of spectroscopy has a straightforward underlying theory. Numerous atom types' nuclei behave like small magnets and frequently align themselves in magnetic fields.
Therefore, the NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.
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1.33 is the answer thank me later
Answer:
A. Actual Yield
Since all of the others are calculated not measured outright.
Based on the information provided and the assumption that the mole ratio of the acid to the base is 1:1, the molarity of the acid would be 0.0425 M
<h3>Acid/base Titration</h3>
Using the equation:
CaVa = CbVb
This is based on the assumption that the stoichiometric mole ratio of the acid to the base is 1:1.
Ca = CbVb/Va
0.1 x 25.5/60 = 0.0425 M
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