When a sodium atom transfers an electron to a chlorine atom, forming a sodium cation (Na+) and a chloride anion (Cl-), both ions have complete valence shells, and are energetically more stable. The reaction is extremely exothermic, producing a bright yellow light and a great deal of heat energy.
Answer : The mass of Ni is, 80.346 g
Solution :
First we have to calculate the number of moles.
Now we have to calculate the number of atoms of 
As 1 moles contains 
number of molecules
So, 1.369 moles contains 
number of molecules
One molecule has one nitrogen atom then number of molecules of will contain number of nitrogen atoms
As per question number of Ni atoms is equal to the number of nitrogen atoms
Number of Ni atoms= atoms
Number of moles = 
Mass of Nickel = 
Molecular mass of Nickel = 58.69 g/mol
Mass of nickel = 
<span>C4H10 + 6.5 O2 ----> 4CO2 + 5H2O
2C4H10 + 13 O2 ----> 8CO2 + 10H2O
1. Count the C on the left (4), put a 4 where the C on the right.
2. Count the H on the left (1), you have two on the right, so you multimply this two by 5. Put the 5 in front of the H2O
3. Count the O on the right. You have 4*2 + 5 = 13. You have two on the left, so you need 6.5 on the left.
4. Now multiply everything on the equation by two so you have nice integer numbers.
5. check you have the same amount of everything on each side.
Example C: left 8, right 8, etc.
I hope this helps. :)</span><span>
</span>
Answer:
See explanation
Explanation:
According to the Journal of Chemical Education, Volume 80, No.8 (2003); "The first ionization energy of bismuth appears to be anomalous......It has been claimed that spin–
orbit coupling by the Russell–Saunders scheme would lower the ground state of Bi+ ..."
However, the involvement of d and f orbitals in Bi and Po implies that the outermost orbitals are poorly screened hence the drop between nitrogen and oxygen is not observed between Bi and Po.
The same argument could be extended to explain the reason why there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B.
You will need to go on yt
