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Inga [223]
4 years ago
7

(–9) • (8) – (9) • (–9)

Mathematics
1 answer:
elena-s [515]4 years ago
7 0

Answer:

10

Step-by-step explanation:


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Four more than twice Kai’s age does not equal Kara’s age. If Kara is 15 years old, find Kai’s age. Let k = Kai's age.
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Just -4 to 15 and the divide
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video streaming company a charges a one-time $40 membership fee and $2 per video stream. video streaming company b charges a one
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Company A:

c = 40 + 2s

Company B:

c = 20 + 4s

Equal costs => 40 + 2s = 20 +4s => 4s - 2s = 40 - 20 => 2s = 20 => s = 20/2

=> s = 10

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Step-by-step explanation:

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22 POINTS !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Mamont248 [21]

Answer:

The dimensions of the park on the scale drawing are 12 inches by 20 inches

The actual dimensions are given as:

Park = 600 feet by 1000 feet

Swing set = 25 feet by 100 feet

The dimension of the swing set on the scale drawing is given as: 0.5 inch by 2 inches

The above means that, the scale factor (k) is:

--- i.e. divide the scale measurement by the actual measurement

Evaluate both equations

So, we have:

Multiply the scale factor by the dimensions of the park, to get the scale measurement

Hence, the dimensions of the park on the scale drawing are 12 inches by 20 inches

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Step-by-step explanation:

3 0
3 years ago
Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra
bearhunter [10]

Answer:

\frac{dh}{dt}=-\frac{1}{2\pi}cm/min

Step-by-step explanation:

From similar triangles, see diagram in attachment

\frac{r}{4}=\frac{h}{16}


We solve for r to obtain,


r=\frac{h}{4}


The formula for calculating the volume of a cone is

V=\frac{1}{3}\pi r^2h


We substitute the value of r=\frac{h}{4} to obtain,


V=\frac{1}{3}\pi (\frac{h}{4})^2h


This implies that,

V=\frac{1}{48}\pi h^3


We now differentiate both sides with respect to t to get,

\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}


We were given that water is drained out of the tank at a rate of 2cm^3/min


This implies that \frac{dV}{dt}=-2cm^3/min.


Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means h=8cm.


We substitute this values to obtain,


-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}


\Rightarrow -2=4\pi \frac{dh}{dt}


\Rightarrow -1=2\pi \frac{dh}{dt}


\frac{dh}{dt}=-\frac{1}{2\pi}






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4 years ago
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