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Elena-2011 [213]
3 years ago
8

What materials does dna polymerase require in order to synthesize a complete strand of dna? select all that apply. select all th

at apply. inorganic phosphate 3'-oh end of the new dna strand all four deoxyribonucleotides triphosphates (containing a, c, t, or g) single-stranded dna template atp?
Biology
1 answer:
Ainat [17]3 years ago
4 0
Answer: <span>inorganic phosphate 3'-oh end of the new DNA strand;
 all four deoxyribonucleotides triphosphates (containing a, c, t, or g) ;
 single-stranded dna template
</span>
<span>DNA polymerase will add free nucleotides only to the 3' end of the new strand but only if there is a  pre-existing 3'-OH group.
The enzyme DNA polymerase will form hydrogen bonds with the nucleotides of the template DNA and add new nucleotides, adenine will bond with thymine and guanine will bond with cytosine.
The replication process has produced a new DNA molecule by using the original strand as a template and the new strand formed which is identical</span>

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The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
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Answer:

2,855 is the size of the colony of mosquitoes after 4 ​days.

Explanation:

The law of uninhibited growth is given as:

A=A_o\times e^{k\times t}

A_o= Original amount

A = Amount after time t

k = Positive constant repressing the rate of growth

We are given with:

Original population of mosquitoes = 1000

Population of mosquitoes after 1 day =1300

t = 1 day

1300=1000\times e^{k\times 1 day}

k = 0.2623 day^{-1}

Population size of mosquitoes after 4 days

A_o=1000, k= 0.2623 day^{-1}

A =? , t = 4 days

A=1000\times e^{ 0.2623 day^{-1}\times 4 days}

A =2,855.36 ≈ 2,855 mosquitoes

2,855 is the size of the colony of mosquitoes after 4 ​days.

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