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Assoli18 [71]
3 years ago
11

3. Use the figure to complete each statement.

Mathematics
1 answer:
ELEN [110]3 years ago
6 0
A. m<BED = 90°

b. axis

c. AB

d. 9

e. E ~ AB
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Find an equation, or a set of equations, to describe the set of points that are equidistant from the points p(−9, 0, 0) and q(3,
wariber [46]
X = -3.  
The distance from p(-9, 0, 0) is
 d = sqrt((x+9)^2 + y^2 + z^2) 
 The distance from q(3,0,0) is
 d = sqrt((x-3)^2 + y^2 + z^2) 
 Let's set them equal to each other.
 sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
  Square both sides, then simplify
 (x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
 x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
 18x + 81 = - 6x + 9
 24x + 81 = 9
 24x = -72
 x = -3 
 So the desired equation is x = -3 which defines a plane.
7 0
3 years ago
Jay is running 6 miles. He has run 2 3 of the total distance. How far has he run to the nearest yard?
podryga [215]

Answer:He has ran 4 miles so far.


Step-by-step explanation:I do not like explaining things okay.


8 0
3 years ago
22x – 54 + 5.736x^4 - 2x^2<br> Standard form
Yuri [45]

Answer:

5.736x^4 - 2x^2 +22x - 54

Step-by-step explanation:

4 0
2 years ago
Find the area of the
erik [133]

Answer:

Option A: 2338.3 cm² is the correct answer.

Step-by-step explanation:

Given that:

The given figure is a regular hexagon.

Length of side = 30 cm

Area of a hexagon is given by;

Area = \frac{3\sqrt{3}}{2}a^2

Putting a=30 in the formula

Area = \frac{3\sqrt{3}}{2}(30)^2

Area = \frac{3\sqrt{3}}{2}*900

Area = 3\sqrt{3}*450

Area = 2338.26 cm²

Rounding off to one decimal place,

Area = 2338.3 cm²

Hence,

Option A: 2338.3 cm² is the correct answer.

3 0
2 years ago
Read 2 more answers
If a= .75 and b= .50, what is the perimeter of the rectangle?
Lerok [7]

Answer:

  C.  14 inches

Step-by-step explanation:

The perimeter is double the sum of length and width:

  P = 2((4a +3) +(6b -2) = 8a +12b +2

For the given values, this is ...

  P = 8(0.75) +12(0.50) +2 = 6 + 6 + 2 = 14

The perimeter is 14 inches.

3 0
3 years ago
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