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nordsb [41]
3 years ago
15

30 points What is the distance between points B and C on the coordinate plane shown below?

Mathematics
1 answer:
Galina-37 [17]3 years ago
3 0

Answer:

looks like 9.5, but kinda hard to tell

You might be interested in
Given: m∠V=103°, m∠VRT=71°, RS ∥ VU Find: m∠TRS, m∠U
lawyer [7]

Answer:

m∠U = 103° and m∠TRS = 6°

Step-by-step explanation:

In the given circle O,

Since, RS║VU, and VR is a transverse,

Therefor, m∠V + m∠R = 180° [Consecutive interior angles]

m∠R + 103° = 180° [m∠R = 103° given]

m∠R = 180° - 103°

m∠R = 77°

Since m∠R = m∠VRT + m∠TRS

77° = 71° + m∠TRS

m∠TRS = 77° - 71° = 6°

Quadrilateral RTUV is a cyclic quadrilateral.

Therefore, m∠U + m∠R = 180°

m∠U + 77° = 180°

m∠U = 180° - 77° = 103°

5 0
3 years ago
A motorist travels from town A to town B, which are 84km apart. If he has completed 7/8 of his journey, what is the distance he
TEA [102]

The distance that he has traveled exists 73km 500m.

<h3>What is the distance?</h3>

Distance exists described as the amount of space between two items or the condition of existing far apart. The distance of an object can be described as the complete path traveled by an object.

Given: A motorist travels from town A to town B, which exists 84km apart. He has finished 7/8 of his journey.

To estimate the distance that he has traveled

He covered 7/8 out of 84 km

So, 7/8 × 84 = 73.5 km

The distance he has traveled = 73 km 500 m

Therefore, the distance that he has traveled exists 73km 500m.

To learn more about distance refer to:

brainly.com/question/26550516

#SPJ9

5 0
1 year ago
Grayson biked 45 miles in 3 hours. Maya biked 26 miles in 2 hours. If they both kept a constant speed, how much faster did Grays
pantera1 [17]

Answer:

Grayson biked at a speed of 15 mph. Maya biked at a speed of 13 mph.

Grayson biked 2 mph faster than Maya.

Step-by-step explanation:

45/3 = 15

26/2 = 13

6 0
3 years ago
QUICKK EXPERTS/ACE/GENIUSES<br> ( question #2 )
kiruha [24]

180 - 90 -18 = 72


Answer is D 72 degrees

3 0
3 years ago
In the equation y=ab^(x-h) +k how does the value of k affect the graph
Ainat [17]

Answer:

  • if k > 0 then the graph of the given equation will get shifted upward by k units.
  • if k< 0 then the graph of the given equation will get shifted downward by k units.

Step-by-step explanation:

We have been given the equation  y=ab^(x-h) +k and we have to state that how the value of k affect the graph.

We know that if we add/subtract some constant in the function value then the translation of the parent graph occurs in the vertical direction.

In other words, the parent graph either get shifted upward or downward depends on the value of the constant.

Therefore, we have

  • if k > 0 then the graph of the given equation will get shifted upward by k units.
  • if k< 0 then the graph of the given equation will get shifted downward by k units.
3 0
3 years ago
Read 2 more answers
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