<span>5×(2-x)+9-7x
=5</span>×2-5<span>×x+9-7x
=10-5x+9-7x
=10+9-(5x+7x)
=19-12x
That's your solution. ^_^</span>
Answer:
Let x = the third side
In a triangle, the sum of any 2 sides must be larger than the third side.
I believe this is called the triangle inequality theorem.
We can construct 3 inequalities to obtain the range of values for the third side.
(Inequality #1) 12 + 4 > x
16 > x
(Inequality#2) 12 + x > 4
x > -8 (we can discard this ... we know all sides will be positive)
(Inequality #3) 4 + x > 12
x > 8
So when we combine these together,
8 < x < 16
X (the third side) must be a number between 8 and 16. but not including 8 and 16
Two multiply 2 monomials, you have to multiply the coefficients and add the degrees. For example
2x^2 × 3x^3 =
6x^5
answer: 1117
the first block is 1000
the second is 100
the third is 10
then the last few count up to 7
