Answer:
The interval of increase of g(x) is 
.
Step-by-step explanation:
The interval of increase occurs when first derivative of given function brings positive values. Let be 
, the first derivative of the function is:
The following condition must be met to define the interval of increase:
The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:
The solution to this inequation is:
Now, the solution to this expression in interval notation is:
50,000×1.04^(15)
=90,047.18
Answer:
Firstly, rewrite the equation:
⅓ (18 + 27) = 81
Substitute x for the given number of it's supposed equivalent.
In this case x = 12.
⅓ (18(12) + 27) = 81
Solve using PEMDAS and simplify what is in the parenthesis first. Then, multiply.
(18 x 12) + 27 = 243
Now, solving using PEMDAS, multiply the total of what you got that was originally in the parenthesis by ⅓ .
⅓ (243) = 81
When you multiple these number they are equivalent to 81.
81 = 81
Since the equation given, when substituted x for 12, is equivalent to 81, this proves that substituting x for 12 makes this equation true.
<h2>
Answer:</h2><h2>
If she continues to throw darts 75 more times, she could predict to hit the
</h2><h2>
bull's-eye 15 times.</h2>
Step-by-step explanation:
Shay found that she hit the bull's-eye when throwing darts 
times = 
.
In five times, she will hit the dart once.
If she continues to throw darts 75 more times,
the probability that she will hit the bull's eye = (75) = 15 times.
If she continues to throw darts 75 more times, she could predict to hit the
bull's-eye 15 times.
