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Korolek [52]
3 years ago
6

In this problem, we will compare the performance of a vector processor with a hybrid system that contains a scalar processor and

a gpu-based coprocessor. in the hybrid system, the host processor has superior scalar performance to the gpu, so in this case all scalar code is executed on the host processor while all vector code is executed on the gpu. we will refer to the first system as the vector computer and the second system as the hybrid computer. assume that your target application contains a vector kernel with an arithmetic intensity of 0.5 flops per dram byte accessed; however, the application also has a scalar component which that must be performed before and after the kernel in order to prepare the input vectors and output vectors, respectively. for a sample dataset, the scalar portion of the code requires 400 ms of execution time on both the vector processor and the host processor in the hybrid system. the kernel reads input vectors consisting of 200 mb of data and has output data consisting of 100 mb of data. the vector processor has a peak memory bandwidth o
Computers and Technology
1 answer:
natka813 [3]3 years ago
3 0
What are you asking??? And this computer whould be considered a super computer! The military uses these type for calibrateing missions hope this helps
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Alchen [17]

The simple interset program is a sequential program, and does not require loops and conditions

The simple interset program in Python, where comments are used to explain each line is as follows:

#This gets input for the principal amount

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#This gets input for the rate

R = int(input("R = "))

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N = int(input("N = "))

#This calculates the simple interest

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2 years ago
An independent penetration testing company is invited to test a company's legacy banking application developed for Android phone
LenaWriter [7]

In the case above, the company can prevent this from happening in the public Internet through the Use certificate pinning.

<h3>Should a person use certificate pinning?</h3>

Mobile applications are known to be one that often make use of   certificate or also public key pinning so that they can be able to make sure that communications are secure.

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Hence, Certificate pinning hinders which certificates are considered valid for a any kind of website,  and as such, In the case above, the company can prevent this from happening in the public Internet through the Use certificate pinning.

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4 0
1 year ago
In most programming languages, the compiler carries a preprocessing step to determine if certain statements will compile. For in
MakcuM [25]

Answer:

See explaination for program code

Explanation:

package com.company;

import java.io.IOException;

import java.nio.file.Files;

import java.nio.file.Paths;

import java.util.Stack;

/*

* A program which reads input from given text filename and prints

* whether it passed the pre-processing stage or not

* Sample input

* int A = (a + b);static void display(int x)

* {

* //A sample input file

* }

* */

public class MyPreprocessor {

/*

* Reads input from filename and returns a string

* containing whole text

* */

public String readInput(String filename) {

String content = "";

try {

content = new String(Files.readAllBytes(Paths.get(filename)));

} catch (IOException e) {

e.printStackTrace();

}

return content;

}

/**

* Filters input since we are only concerned with

* a subset of input = '{}[]()/*'

*/

public String filterText(String text) {

String output = "";

for(int i = 0;i<text.length();++i) {

switch (text.charAt(i)) {

case '[':

case ']':

case '{':

case '}':

case '(':

case ')':

case '*':

case '/':

output += text.charAt(i);

}

}

return output;

}

/*

* Uses stack to determine if input is valid or not

* */

public boolean parse(String input) {

Stack<Character> St = new Stack<Character>();

// '$' is special symbol to represent bottom of stack

St.push('$');

for(int i = 0;i<input.length();++i) {

Character symbol = input.charAt(i);

if(St.peek().equals(getOpenSymbol(symbol)))

St.pop();

else St.push(symbol);

}

return St.peek() == '$';

}

private static Character getOpenSymbol(Character symbol) {

switch (symbol) {

case '}': return '{';

case ']': return '[';

case ')': return '(';

case '*': return '*';

case '/': return '/';

default: return ' ';

}

}

public static void main(String[] args) {

MyPreprocessor preprocessor = new MyPreprocessor();

String inputText = preprocessor.readInput("src/input.txt");

String filteredInput = preprocessor.filterText(inputText);

if(preprocessor.parse(filteredInput))

System.out.println("preprocessing passed.");

else System.out.println("preprocessing failed!");

}

}

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I think it’s b false sorry if I was wrong
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In ipv4 addressing, each ip address is a unique ____ number.
Natali5045456 [20]
32-bit is the correct answer to this question.
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