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anyanavicka [17]
4 years ago
15

Need this please help

Mathematics
1 answer:
scoray [572]4 years ago
4 0

Answer:

Step-by-step explanation:

a) Steps to prove that two triangles are similar are

1) AA(angle angle)if two angles of each triangle is congruent to two angles of another triangle, then the third angles of both triangles must be congruent since the sum of angles in the triangle is 180 degrees

2) SSS(side side side) if the three sides of both triangles are proportional to each other, then the triangles are similar.

3) SAS(side angle side) if two sides of a triangle are proportional to two sides of another triangle and and the angle formed by both lines in the two triangles are equal, then the third sides of both triangles are proportional. Therefore, the triangles are similar.

b) triangle ABC would be similar to triangle QRS if

1) angle A is congruent to angle Q and angle B is congruent to angle R

2)if the ratio of AB to QR is proportional to the ratio of AC to QS, and to BC to RS

3) if AC is proportional to QS, AB is proportional to QR and angle A = angle Q

c) AC/AB = QS/QR

60/50 = 6/QR

6/5 = 6/QR

6QR = 6×5 = 30

QR = 30/6 = 5 cm

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The expression can be simplified to a polynomial of degree 2.

x^2 - 10x + 2

<h3>How to simplify the expression?</h3>

Here we have the expression:

(3x^2 -11x - 4) - (2x^2 - x - 6)

We can directly simplify this by taking the variable as common factor:

(3 - 2)*x^2 + (-11 + 1)*x + (-4 + 6)\\\\x^2 - 10x + 2

This is a polynomial, as you can see, the maximum exponent is 2, so the degree of the polynomial is 2.

If you want to learn more about polynomials:

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3 years ago
Whats the answer and how do i get the answer myself
Mumz [18]

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3 years ago
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