Question

Whats the answer and how do i get the answer myself

Answer 1

Answer:

$f^{-1} (x) = \frac{x}{3} - 3$

Step-by-step explanation:

Let here the given function f(x) = y

or, $x= f^{-1} (y)$

⇒  y = 3x+ 9

Now, solving for x, we get

3x+ 9 = y ⇒  3x = y - 9

or, $x = \frac{y-9}{3} = \frac{y}{3} - \frac{9}{3}$

⇒   $x = ( \frac{y}{3}) - 3$

Now, substituting x and y

Hence, $f^{-1} (x) = \frac{x}{3} - 3$