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Fofino [41]
4 years ago
12

Which table represents a function??

Mathematics
2 answers:
nalin [4]4 years ago
5 0
The table that represents a function is the -5,-5 0,0 -5,5 and 6,-6
faust18 [17]4 years ago
3 0
The 1st Option Is A Function
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Make the denominator the same. the answer is 8/12 of the can
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What is the answer to A x + B y = C
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means that ab=c

Step-by-step explanation:

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3 years ago
Given uv = su tu sv prove vt = st
Lady bird [3.3K]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\begin{array}{cl|cl}&\underline{\text{Statement}}&&\underline{\text{Reason}}\\1.&TU\perp SV&1.&\text{Given}\\2.&\angle TUV = 90^o&2.&\text{De finition of Perpendicular angles}\\&\angle TUS = 90^o&&\\3.&\angle TUV=\angle TUS&3.&\text{Transitive Property}\\4.&UV=US&4.&\text{Given}\\5.&TU=TU &5.&\text{Reflexive Property}\\6.&\triangle TUV = \triangle TUS&6.&\text{SAS Congruency Theorem}\\7.&VT=ST&7.&CPCTC\end{array}

5 0
4 years ago
Which equation can be used to solve the following word problem? Seth has 8 more nickels than dimes, and the total value of his c
9966 [12]

Answer:

Seth has 21 nickels

Step-by-step explanation:

Let n represent the number of nickels. Since Seth has 8 more nickels than dimes, then (n-8) is the number dimes.

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5n+10(n-8)=235.

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5n+10n-80=235,\\ \\15n=235+80,\\ \\15n=315,\\ \\n=21.

6 0
3 years ago
In a candy mix there are 4 green bars for every 3 red bars. How many red bars are there if there are 200 green bars
erastovalidia [21]

Answer:

Since there are 4 green bars for every 3 red bars and we are trying to find the number of red bars if there are 200 green bars, we can create the ratio:

4 x : 3 y

Where  x  is equal to the number of green bars and  y is the number of red bars.

We know the number of green bars is equal to 200, so we can divide it by 4, giving us:

200 /4=50

Then we can solve for  y , the number of red bars.

// Multiple y  by 50

3 ⋅ 50 = 150

So for every 4 green bars, there are 3 red bars.

For every 200 green bars, there are 150 red bars

Step-by-step explanation:

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3 years ago
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