Answer:
should be "d" though i haven't calculated it all exactly
Step-by-step explanation:
A : 85
B : 83
C : 82
D : 81
Given:
![f(x)=\sqrt[]{5x^2-2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5D%7B5x%5E2-2%7D)
f(X) will be differentiated by chain rule.
To find the area of a rectangle, multiple the width by the length.
(And simply the fractions for a simpler equation)
For piece A:
The length 1 and 3/5 can be turned into an improper fraction by multiplying 1 by the denominator (5) and adding it to the numerator (3). 1 and 3/5 = 8/5
(3/4) • (8/5) = area
Multiple the numerators with each other and the denominators with each other (3 times 8 = 24) (4 times 5 = 20)
The area of piece A is 24/20
If you do the same for piece B:
(2/5) • (21/8) = area
The answer is 42/40
1. Adjacent means they are next to each other and share equal common side and vertex. So its angleRUS and angleSUT.
2. If you see that little square that equals to 90 degrees so it’s the same thing as the adjacent
3. and M should be the line between V and T
You would subitute -2 for x in the equation
f(-2)=x^2-6
PEMDAS so exonents
-2^2-6
negative times a negative= positive
4-6
f(-2)=-2
f(x) means that you subsitute x for x in the equation exg
f(1)=x+2 means f(1)=1+2
f(4)=x+2 means f(4)=4+2