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Ipatiy [6.2K]
3 years ago
6

URGENT HELP PLEASE!

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

Perpendicular lines (c)

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Which triangles are congruent? How do you know?
choli [55]
Use the side lengths! C and D have lengths of 3 and heights of 4.
Also use how far away they are from the axis.

Both C and D are 2 away from each axis on the end point.
This also goes with A.
However, B does not seem to be congruent in the sense of (coordinates)
It is the same length and height.
3 0
3 years ago
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I CAN HEELP WITH SPANISH STUFF PLEASE HELP MEEE
Marizza181 [45]

Answer:

i believe 48 is 5

Step-by-step explanation:

6 0
3 years ago
The product shown is a difference of squares. What is the missing constant term in the second factor?
34kurt
Difference of two squares is of the form (a + b)(a - b) or vice-versa. Here, a = -5x and b = 3.
(-5x - 3)(-5x + 3)
Answer: 3
7 0
3 years ago
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Find the vertex of the graph of the function.
lapo4ka [179]

Answer: The correct options are  (1) (5,10), (2) (3,-3), (3) x = -1, (4) y=(x+2)^2+3, (5) 21s and (6) 0, -1, and 5.

Explanation:

Te standard form of the parabola is,

f(x)=a(x-h)^2+k        .....(1)

Where,  (h,k) is the vertex of the parabola.

(1)

The given equation is,

f(x)=(x-5)^2+10

Comparing this equation with equation (1),we get,

h=5 and k=10

Therefore, the vertex of the graph is (5,10) and the fourth option is correct.

(2)

The given equation is,

f(x)=3x^2-18x+24

f(x)=3(x^2-6x)+24

To make perfect square add (\frac{b}{2a})^2, i.e., 9. Since there is factor 3 outside the parentheses, so subtract three times of 9.

f(x)=3(x^2-6x+9)+24-3\times 9

f(x)=3(x-3)^2-3

Comparing this equation with equation (1),we get,

h=3 and k=-3

Therefore, the vertex of the graph is (3,-3) and the fourth option is correct.

(3)

The given equation is

f(x)=4x^2+8x+7

f(x)=4(x^2+2x)+7

To make perfect square add (\frac{b}{2a})^2, i.e., 1. Since there is factor 4 outside the parentheses, so subtract three times of 1.

f(x)=4(x^2+2x+1)+7-4

f(x)=4(x+1)^2+3

Comparing this equation with equation (1),we get,

h=-1 and k=3

The vertex of the equation is (-1,3) so the axis is x=-1 and the correct option is 2.

(4)

The given equation is,

y=x^2+4x+7

To make perfect square add (\frac{b}{2a})^2, i.e., 2^2.

f(x)=x^2+4x+4+7-4

f(x)=x^2+4x+4+7-4

f(x)=(x+2)^2+3

Therefore, the correct option is  4.

(5)

The given equation is,

h=-16t^2+672t

It can be written as,

h=-16(t^2-42t)

It is a downward parabola. so the maximum height of the function is on its vertex.

The x coordinate of the vertex is,

x=\frac{b}{2a}

x=\frac{42}{2}

x=21

Therefore,  after 21 seconds the projectile reach its maximum height and the correct option is first.

(6)

The given equation is,

f(x)=3x^3-12x^2-15x

f(x)=3x(x^2-4x-5)

Use factoring method to find the factors of the equation.

f(x)=3x(x^2-5x+x-5)

f(x)=3x(x(x-5)+1(x-5))

f(x)=3x(x-5)(x+1)

Equate each factor equal to 0.

x=0,-1,5

Therefore, the zeros of the given equation is 0, -1, 5 and the correct option is 2.

3 0
3 years ago
Use the distributive property to factor the expression below.
Tems11 [23]

Answer:

D. 5(x^2+5)

Step-by-step explanation:

5x^2+25

Viewing the two terms 5 is divisible by both

5X^2/5 +25/5

X^2+5

Therefore the equation will be represented by

5(x^2+5)

4 0
3 years ago
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