First you need to get rid of the parenthesis by distributing the 0.6 to each term inside.
(0.6)(10n) + (0.6)(25) =10+5n
6n +15 = 10+5n subtract the 5n on both sides and subtract 15 from both sides
6n-5n = 10-15
n=-5
The correct answer is d 7/7
Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
Answer:
The correct answer is D. -2,592, -15,552, -93,312
Step-by-step explanation:
Each of the terms is the previous term multiplied by 6. You can find this by taking any term and dividing it by the one before it. The answer will always be 6.
-72/-12 = 6
-12/-2 = 6
So, in order to find the next 3, we take the last term and multiply it by 6.
-432 * 6 = -2,592
-2,592 * 6 = -15,552
-15,552 * 6 = -93,312
The answer is 1 because4 is close to 5