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Zina [86]
2 years ago
13

Find the distance of the following points from the x axis: P(3,0) , Q(0,-3) , R(12,-4) , S(-4,-3)

Mathematics
1 answer:
OverLord2011 [107]2 years ago
7 0

Answer:

Distance of point P(3,0) from x axis is zero as this point lies on x axis.

distance of point Q is 3.

Distance of point R is 4.

Distance of point S is 3.

Step-by-step explanation:

Point P already lies on x axis as its y coordinate is zero so its distance from x axis is zero

distance of points Q , R and S is the absolute value of their y coordinates that is 3 , 4 and 3 respectively.

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Answer:

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Step-by-step explanation:

Normal Distribution

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Standard deviation 4,8

1.- Test hypothesis

H₀             null hypothesis        ⇒               μ₀ = 14       and

Hₐ     alternative hypothesis   ⇒                μ₀ ≠ 14

2.- z(c)  we assume α = 0,05  as we are dealing with a two test tail we should  consider   α/2  = 0.025.

From z table we the z(c) value

z(c) = 1.96           and of course by symmetry   z(c) = -1.96

3.- We proceed to compute z(s)

z(s)  = [ (  μ -  μ₀ ) /( σ/√n) ]           ⇒    z(s)  = - (1.5)*√64/4.8

z(s)  = - 2.5

We compare z(s)  and z(c)

z(s) < z(c)     -2.5  < -1.96  meaning  z(s) is in the rejection zone

we reject H₀ .

From the start we indicate sample size as to small for the experiment nonetheless we found that we dont have enough evidence to accept H₀

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Step-by-step explanation:

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