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Mazyrski [523]
3 years ago
8

The slope of the line below is 4. Which of the following is the point-slope form

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0
Y-(-4) = 4(x-(-3))

Y+4 = 4(x+3)

The answer is A


Hope this helps!
damaskus [11]3 years ago
5 0

Answer:

A: y+4=4(x+3)

Step-by-step explanation:

Point-Slope Formula:

y-y1=m(x-x1)

Substitute:

y-(-4)=4(x-(-3))

-(-)=+

P: y+4=4(x+3)

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Step-by-step explanation:

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5 0
3 years ago
A group of 22 students participated in a race. Their scores are below: Score (points) 4–5 6–7 8–9 10–11 12–13 Number of Students
Anna71 [15]
A histogram would best represent the data.
Dot plot is a good way to show a certain trend. However, when it comes to the number of a item, in this case the number of students in a certain score range, a histogram will be the most intuitive and concise. Thus, a histogram best represent the data presented here.
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3 years ago
How do you solve 2(y + 1) – 2 = 4 + 2y - y
Elina [12.6K]

Answer:

y=4

Step-by-step explanation:

2(y+1)-2=4+y

2y+2-2=4+y

2y=4+y

2y-y=4

y=4

7 0
3 years ago
Read 2 more answers
How do I turn 7 over 8 divided by 2 over 5 into a mixed fraction
tangare [24]
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5 0
3 years ago
Find a parametric representation for the part of the cylinder y2 + z2 = 49 that lies between the planes x = 0 and x = 1. x = u y
sweet-ann [11.9K]

Answer:

The equation for z for the parametric representation is  z = 7 \sin (v) and the interval for u is 0\le u\le 1.

Step-by-step explanation:

You have the full question but due lack of spacing it looks incomplete, thus the full question with spacing is:

Find a parametric representation for the part of the cylinder y^2+z^2 = 49, that lies between the places x = 0 and x = 1.

x=u\\ y= 7 \cos(v)\\z=? \\ 0\le v\le 2\pi \\ ?\le u\le ?

Thus the goal of the exercise is to complete the parameterization and find the equation for z and complete the interval for u

Interval for u

Since x goes from 0 to 1, and if x = u, we can write the interval as

0\le u\le 1

Equation for z.

Replacing the given equation for the parameterization y = 7 \cos(v) on the given equation for the cylinder give us

(7 \cos(v))^2 +z^2 = 49 \\ 49 \cos^2 (v)+z^2 = 49

Solving for z, by moving 49 \cos^2 (v) to the other side

z^2 = 49-49 \cos^2 (v)

Factoring

z^2 = 49(1- \cos^2 (v))

So then we can apply Pythagorean Theorem:

\sin^2(v)+\cos^2(v) =1

And solving for sine from the theorem.

\sin^2(v) = 1-\cos^2(v)

Thus replacing on the exercise we get

z^2 = 49\sin^2 (v)

So we can take the square root of both sides and we get

z = 7 \sin (v)

4 0
3 years ago
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