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Vladimir [108]
3 years ago
9

Consider two unique parallel lines. What aspects of these two lines are the same? What aspects of these two lines would have to

be different? Explain your reasoning.
Mathematics
2 answers:
kenny6666 [7]3 years ago
8 0

Answer:

Two parallel lines will have the same slope. The slopes of parallel lines have to be equal. The y-intercepts of those two lines have to be different, otherwise they would be the same line. The x-intercepts of the parallel lines would also be different.  hope it helps

Step-by-step explanation:

scoray [572]3 years ago
7 0
Parallel lines must have the same slope.  However for them to be UNIQUE lines, ie different lines, they must have a different y-intercept.

So if we say generally that a line is y=mx+b where m is the slope and b is the y-intercept then these two unique parallel lines would be:

y1=mx+h and y2=mx+k

Where m is the same for both and each have unique constants h and k where they cross the y-axis
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A line passes through the point (-8, 6) and has a slope of -5/4.
Margarita [4]

Answer:

y = -5/4x - 4

Step-by-step explanation:

Plug in 6 for y and -8 for x. Then solve for b or "y-intercept". You should get -4

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3 years ago
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A recent tornado damaged Jack's house and left it a little distorted. A question on the insurance form asked, "What shape is the
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45

Step-by-step explanation:

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3 years ago
A. Is this an arithmetic sequence? How do you know?
pogonyaev

Answer:

a. Yes. The difference is common and equal to $1750

b. $1750

c. $20000 was initial investment

d. This is linear equation with start point of 20000 and slope of 1750:

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e. After another 10 years (on the top of 5 given) the investment will be:

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The table shows the total number of pictures Cal took by the end of each week.
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Guys please help! In triangle CDE, the measure of angle C is 90 degrees, side CD is 15 and DE is 3 more than CE. Find the length
AURORKA [14]
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)

your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°

-> insert those values, with c substituted with b+3 to remove c

c^2=a^2+b^2-2*a*b*cos(C)
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cos(90)=0->
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DE=CE+3=36+3=39
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3 years ago
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