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3 years ago

Can someone tell me the answer to this question

Mathematics

1 answer:

Firdavs [7]3 years ago

5 0

If these two lines are parallel, they would have the same gradient.

Since Gradient = Rise / Run,

8 / -12 : -4 / 1

These two ratios are obviously not the same, so we can conclude the lines are not parallel.

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10 POINTS AND BRAINLIEST! PLEASE ANSWER BOTH QUESTIONS!

jok3333 [9.3K]

Segment CF is parallel to segment BE because these segments are side by side and will have the same distance continuously between them. Therefore your answer would be,

Segment BE

∠AOF is the angle that is the supplementary angle to ∠FOD because these are two angles that sum up to 180°. hence, the answer is,

∠AOF

8 0

3 years ago

Find the area and perimeter of a rectangle if<br> the length is 25 and the width is 8.

g100num [7]

Answer:

area is 200 perimeter is 66

Step-by-step explanation:

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3 years ago

Please help!! I don’t understand how to solve this

belka [17]

Answer:it is c

Step-by-step explanation:

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2 years ago

Find the mean absolute deviation for the set s={85, 90, 68, 75, 79}

FromTheMoon [43]

Answer: 6.48

Step-by-step explanation:

Mean is 79.4, population size is 5

MAD formular is addition of variance point /population size

n∑∣xi−xˉ∣

8 0

3 years ago

There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc

sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and B be the event that student play soccer.

$P(A)=8\%$

$P(B)=14\%$

It is given that 6 students play on both teams.

$P(A\cap B)=\frac{6}{200}\times 100=3\%$

We have to find the probability that a student plays either basketball or soccer.

$P(A\cup B)=P(A)+P(B)-(A\cap B)$

$P(A\cup B)=8\%+14\%-3\%$

$P(A\cup B)=19\%$

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

6 0

3 years ago