Deondra has $420 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.

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snow_lady [41]

Answer:

3x + 2 = 59

Step-by-step explanation:

because the total is 59 so is definetly =59

and no of oranges in bag so there are 3 bags it means its 3x so the equation is 3x + 2 = 59

Hope it will help you

Lots of love from nepal <3 :)

5 0

3 years ago

NEED HELP IN FIVE MINUTE PLZ HURRY

Y_Kistochka [10]

Answer:

R=.2,P=.25, G=.55

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone please help me with this

timofeeve [1]

Answer:

x= 6

Step-by-step explanation:

since both sides equal the same amount..

5x-7=3x+5

you plug it in through a calculator or work it out. if you dont know how to work it out, try the app photomath, it shows you solving steps :))

8 0

3 years ago

The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g

Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

Step-by-step explanation:

This is a problem of the distribution of sample means. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves normally for samples sizes equal or greater than 30 $\\ n \geq 30$ . Mathematically

$\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$ [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a normal standard distribution, i.e., a normal distribution that has a population mean $\\ \mu = 0$ and a population standard deviation $\\ \sigma = 1$ .

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [2]

From the question, we know that

The population mean is $\\ \mu = 88$ WPM
The population standard deviation is $\\ \sigma = 14$ WPM

We also know the size of the sample for this case: $\\ n = 137$ sixth graders.

We need to estimate the probability that a sample mean being greater than $\\ \overline{X} = 89.87$ WPM in the distribution of sample means. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}$

$\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}$

$\\ Z = 1.5634 \approx 1.56$

This is a standardized value and it tells us that the sample with mean 89.87 is 1.56 standard deviations above the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any cumulative standard normal table available in Statistics books or on the Internet. Of course, this probability is the same that $\\ P(\overline{X} < 89.87)$ . Then

$\\ P(z$

However, we are looking for P(z>1.56), which is the complement probability of the previous probability. Therefore

$\\ P(z>1.56) = 1 - P(z$

$\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594$

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

5 0

3 years ago

What is the domain restrictions for x=-6 and x=1

slavikrds [6]

Answer:

the domain in general is negative Infinity, infinity.

Step-by-step explanation:

Infinity means it is a straight line that goes on forever it never stops. graph the -6 and 1. I am not totally sure what domain restrictions are if you have an equation for it go a head and put it there and I can help you more.

8 0

3 years ago