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AURORKA [14]
3 years ago
7

How do you solve x^2+11x+18=0 with either quadratic formula. factoring. or squarerooting

Mathematics
2 answers:
Lostsunrise [7]3 years ago
3 0
I always prefer factoring, if there are simple factors.
There are simple factors here.

x² + 11x + 18 = 0

(x + 2) (x + 9) = 0

The left side is zero if either factor is zero.

First factor:
x + 2 = 0
<u>x = -2</u>

Second factor:
x + 9 = 0
<u>x = -9 </u>

 
Juli2301 [7.4K]3 years ago
3 0
quadratic\ formula:\\\\x^2+11x+18=0\\\\a=1;\ b=11;\ c=18\\\\\Delta=b^2-4ac;\ \Delta=11^2-4\cdot1\cdot18=121-72=49\\\\x_1=\frac{-b-\sqrt\Delta}{2a}\to x_1=\frac{-11-\sqrt{49}}{2\cdot1}=\frac{-11-7}{2}=\frac{-18}{2}=-9\\\\x_2=\frac{-b+\sqrt\Delta}{2a}\to x_2=\frac{-11+7}{2\cdot1}=\frac{-4}{2}=-2
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Help me please. I am having troubles with my math homework.
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Answer: (3) f(8) = g(8)

<u>Step-by-step explanation:</u>

Let's compare the values of f(x) and g(x) when x = 0, 2, 8, and 4

<u>      f(x)       </u>                      <u>      g(x)        </u>            <u>Comparison</u>

f(x) = 2x - 3                     g(x)=\dfrac{3}{2}x+1

f(0) = 2(0) - 3                     g(0)=\dfrac{3}{2}(0)+1

      = -3                                   = 1                     f(0) < g(0)

f(2) = 2(2) - 3                     g(2)=\dfrac{3}{2}(2)+1

     = 1                                      = 4                     f(2) < g(2)

f(8) = 2(8) - 3                     g(8)=\dfrac{3}{2}(8)+1

     = 13                                   = 13                     f(8) = g(8)

f(4) = 2(4) - 3                     g(4)=\dfrac{3}{2}(4)+1

      = 5                                   = 7                       f(4) < g(4)


The only statement provided that is true is f(8) = g(8)




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