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1 year ago

3.873... express in p/q form

1 answer:

7 0

387/100
p/q formula

The theorem states that each rational solution x = p⁄q, written in lowest terms so that p and q are relatively prime, satisfies: p is an integer factor of the constant term a0, and.

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Suppose that x and y vary inversely and x = 1 when y =5. Write a function that models the inverse variation Graph the function a

Vaselesa [24]

The answer is a function

3 0

2 years ago

Solve l 3x-7 l = 2

Lelechka [254]

Answer:

1) Solutions are x = 3 and x = 5/3

2) Solution are x ≤ 13/2 and x ≤ -3/2

Step-by-step explanation:

1) Given absolute inequality,

|3x-7| = 2

⇒ 3x - 7 = ± 2

⇒ 3x = 7 ± 2

$\implies x=\frac{7\pm 2}{3}$

$x=\frac{7+2}{3}\text{ or }x=\frac{7-2}{3}$

$\implies x = 3\text{ or }x=\frac{5}{3}$

2) l 2x-5 l ≤ 8

⇒ 2x-5 ≤ ±8

⇒ 2x ≤ 5 ± 8

$\implies x\leq \frac{5\pm 8}{2}$

$x\leq \frac{5+8}{2}\text{ or }x\leq \frac{5-8}{2}$

$\implies x \leq \frac{13}{2}\text{ or }x\leq-\frac{3}{2}$

8 0

2 years ago

Read 2 more answers

Y=2(x+4)^2-21<br><br> Convert the equation from vertex form to standard

PSYCHO15rus [73]

Answer:

y = 2x² + 16x + 11

I hope im right... If not reaaally sorry!!

7 0

3 years ago

-2x^2+4x-1 from 6x^2+3x-9

kirza4 [7]

Answer:

$8{x}^{2} - x - 8$

Step-by-step explanation:

We want to subtract

$- 2 {x}^{2} + 4x - 1$

from

$6 {x}^{2} + 3x - 9$

We set up the subtracttion problem to get:

$6 {x}^{2} + 3x - 9 - ( - 2 {x}^{2} + 4x - 1)$

We expand the parenthesis to get:

$6 {x}^{2} + 3x - 9 + 2 {x}^{2} - 4x + 1$

Group similar terms:

$6 {x}^{2} + 2 {x}^{2} + 3x- 4x + 1 - 9$

We simplify to get:

$8{x}^{2} - x - 8$

4 0

3 years ago

Solve T=C(5+ AB) for B.

Vaselesa [24]

Answer:

$b = \frac{t - 5}{a}$

Step-by-step explanation:

$t = c(5 + ab)$

Simplify:

$t = 5c + abc$

Move 5c to the other side:

$t - 5c = abc$

Divide bother sides with AC:

$\frac{t - 5c}{ac} = \frac{abc}{ac}$

Simplify:

$\frac{t - 5}{a} = b$

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8 0

1 year ago