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2 years ago

3.873... express in p/q form

1 answer:

7 0

387/100
p/q formula

The theorem states that each rational solution x = p⁄q, written in lowest terms so that p and q are relatively prime, satisfies: p is an integer factor of the constant term a0, and.

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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is . What is the standard form of the

kvasek [131]

Answer:

Point-Slope form: $y+1=-\frac{6}{15}(x+5)\\$

standard form: $2x+5y=-15$

Step-by-step explanation:

The standard form is given by: $Ax+By=C$

The point-slope form is given by: $y-y_1=m(x-x_1)$

Let's call $(-5,-1)$ as point $(x_1,y_1)$ , and

point $(10,-7)$ as point $(x_2,y_2)$

We also know that the slope $m$ is given by $m=\frac{y_2-y_1}{x_2-x_1}$

Let's find the slope:

$m=\frac{-7-(-1)}{10-(-5)}=-\frac{6}{15}$

1. So, point slope form can be written as:

$y-(-1)=-\frac{6}{15}(x-(-5))\\y+1=-\frac{6}{15}(x+5)\\$

2. Rearranging this equation and bringing all x's and y's to one side and the number to another side will give us the standard form. So:

$y+1=-\frac{6}{15}x-2\\y+\frac{6}{15}x=-2-1\\y+\frac{6}{15}x=-3$

But A, B, and C (standard form) needs to be integers, so to get rid of the denominator , we multiply the whole equation by 15. So we have:

$y+\frac{6}{15}x=-3\\15y+6x=-45$

We can factor out a 3, so it becomes:

$15y+6x=-45\\5y+2x=-15$

So standard form is $2x+5y=-15$

8 0

4 years ago

There are many ways to produce crooked dice. To load a die so that 6 comes up too often and 1 , which is opposite 6 , comes up t

Andreas93 [3]

Answer:

1 2 3 4 5 6

2 ÷ 15 1 ÷ 6 1 ÷ 6 1 ÷ 6 1 ÷ 6 1 ÷ 5

Step-by-step explanation:

As it is mentioned in the question that the probability of faces like 2,3,4,5 are not affected so in this case

P(2) = P(3) = P(4) = P(5) = 1 ÷ 6

And, P(6) = 0.2

As we know that

P(1) + P(2) +P(3) +P(4) +P(5) +P(6) = 1

This results P(1) = 2 ÷ 15

So,

1 2 3 4 5 6

2 ÷ 15 1 ÷ 6 1 ÷ 6 1 ÷ 6 1 ÷ 6 1 ÷ 5

Hence, the correct option is 2nd

4 0

3 years ago

Una empresa fabrica dos modelos de DVD: el modelo A y el modelo B. Se dispone de 50 kilogramos de caucho y de 80 horas de mano d

alexandr1967 [171]

Answer:

¿Cuántos DVD de cada tipo debe fabricar y vender para que la utilidad sea máxima?

Se debe fabricar y vender 20 DVD del modelo A y 30 DVD del modelo B. La utilidad máxima es de de S/. 1 800

Step-by-step explanation:

x : Número de DVD del modelo A

y : Número de DVD del modelo B.

MODELO A MODELO B TOTAL

Cantidad de caucho 1x 1x 50 kg.

Horas de mano de obra 1x 2x 80 horas

U : Utilidad mensual.

La función objetivo, que se debe maximizar, es:

U=30 + 40y

x+ y $\leq 50\\$

x + 2y $\leq 80$

x $\geq 0$

y $\geq 0$

Las coordenadas de los vértices de la región factibles son:

A (0, 0) B (50, 0) C (20, 30) D(0, 40)

Entonces, se evalúa la función objetivo en cada punto:

U (0, 0) = 30 (0) + 40 (0) = 0

U (50, 0) = 30 (50) + 40(0) = 1500

U (90, 0) = 30 (20) + 40 (30) = 1800

U (0, 40) = 30 (0) + 40 (40) =1600

Por consiguiente U tiene un valor máximo en C , en donde: x =20 , y = 30 .

Se debe fabricar y vender 20 DVD del modelo A y 30 DVD del modelo B. La utilidad máxima es de de S/. 1 800.

 30 x  40 y

s.a.



 x  0 (3)

 y  0 (4)

3 0

3 years ago

Two hundred dollars is increased by 25% and the result decreased by 25%

erastova [34]

Answer:

If $200 increased by 25%, your result would be $250

If it then decreased by 25%, your result would be $187.5

Step-by-step explanation:

Multiply 200 and 25% and add 200 to get 250

Multiply 250 and 25% and then add that value to get 187.5

5 0

3 years ago

Read 2 more answers

Suppose the students who scored 85 and 90 on the math test take the test again score 95

hodyreva [135]

That means they went up by 10 points or 5 points

7 0

4 years ago