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Ivenika [448]
2 years ago
13

3.873... express in p/q form

Mathematics
1 answer:
Lemur [1.5K]2 years ago
7 0
387/100
p/q formula

The theorem states that each rational solution x = p⁄q, written in lowest terms so that p and q are relatively prime, satisfies: p is an integer factor of the constant term a0, and.
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John plays basketball at the local gym. The gym charges a monthly membership fee of $15.00, plus each player pays $2.50 per game
Katyanochek1 [597]
Answer:
Step-by-step explanation:
Assuming that for each option, you play the same number of games,x
Let y represent the cost of playing x games using option A
Option A is to buy a membership card and pay $2 every time you go to the gym. The membership card costs $20. It means that
y = 20 + 2x
Let z represent the cost of playing x games using option B
Option B is to pay $4 each time you go. It means that
z = 4x
To determine how many games will be played before cost of option A equal to the cost of option B, we would equate y to z. It becomes
20 + 2x = 4x
4x - 2x = 20
2x = 20
x = 20/2 = 10
It will take 10 games for both to be the same
3 0
3 years ago
Read 2 more answers
And help me with B C D
WARRIOR [948]
B has the equation -2 + 7 = -5
C has the equation -7 + 5 = -2
D has the equation 5 + (-7) = -2
3 0
3 years ago
What is (6^3)^4 simplified
Sophie [7]

Step-by-step explanation:

( {6}^{3})^{4}   =  {6}^{3 \times 4}  =  {6}^{12} \\

7 0
3 years ago
WILL GIVE BRAINIEST AND POINTS :
crimeas [40]

Answer:

BE = FC = 3 inches, EF = 2 inches

Step-by-step explanation:

The sum of angles A and D is 180°, so the sum of their half-angles is 90°. That is, half of A plus half of B add to 90°, so the bisector from B intersects AE at a right angle. Call that point of intersection X.

Then angle ABX = angle EBX, so triangle ABX is congruent to triangle EBX. Sides AB and BE are corresponding sides of congruent triangles.

The same argument applies to sides DC and CF.

Thus we have BE = CF = 3 inches, and EF is the left-over distance, 2 inches.

7 0
3 years ago
A population of 100 frogs increases at an annual rate of 22%. How many frogs will there be in 5 years? Write an expression to re
gizmo_the_mogwai [7]
Exponential growth of the form:

F=Ar^t

F=100(1.22)^t

F(5)=100(1.22)^5

F(5)=270.27

F(5)=270 to the nearest frog...

....

1.22=r^12

r=1.22^(1/12)

F=100(1.22^(1/12)^t)

F=100(1.22^(t/12))  now it will produce monthly populations...

Say we did the same as before but instead of 5 years you have 60 months...

F(60)=100(1.22^(60/12))

F(60)=270 to the nearest frog... :P 
6 0
3 years ago
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