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3 years ago

(2/3x+20)+2x=90 i dont know where to start with this equation

Mathematics

2 answers:

LiRa [457]3 years ago

8 0

Answer:

26 1/4

Step-by-step explanation:

start by converting 2x to 6/3 x so your x coefficients have common denominators and can be added

2/3 + 6/3 = 8/3

8/3 x = 70

multiply both sides by 3/8 to move the 8/3 to the other side.

x = 210/8 or 26 1/4

Dimas [21]3 years ago

8 0

Answer-

x=104/3

Step-by-step explanation:

1. (2x)+(2/3+20)=90 (combine like terms)

2. 2x+62/3=90

3. subtract 63/3 from both sides 2x+62/3-62/3=90-62/3

The answer you get is 2x=208/3 but you need to divide it by 2 so

2x/2= x and 208/2=104/3

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-3q + 12 greater than equal too 4q - 30 solve for q

valentina_108 [34]

Solving the inequality $-3q+12\geq 4q-30$ the value of q is $q\leq 6$

Step-by-step explanation:

We need to solve the inequality: $-3q+12\geq 4q-30$ and find value of q

Solving:

$-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6$

So, solving the inequality $-3q+12\geq 4q-30$ the value of q is $q\leq 6$

Keywords: Solving inequality

Learn more about solving inequality at:

#learnwithBrainly

6 0

3 years ago

Can you help me pls

Galina-37 [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

During a football game a concert in stenciled family three hamburgers and two white dogs for a total of $13 and another family t

jeka94

Answer:

Price of hamburgers = $2

Price of white-dogs = $3

Step-by-step explanation:

Let

The number price of hamburgers be x

The number price of white-dogs be y

Then the first family buys 3 hamburgers and 2 white -dogs for $13

3x + 2y = 13-----------------------------(1)

Another first family buys 2 hamburgers and 5 white -dogs for $16

2x + 5y = 16----------------------------(2)

To solve let us multiply eq(1) by 2 and eq(2) by 3, we get

6x + 4y = 26-----------------------------(3)

6x + 15y = 48----------------------------(4)

subracting (3) from (4)

6x + 15y = 48

6x + 4y = 26

(-)

-------------------------

11y = 22

---------------------------

$y =\frac{22}{11}$

y =2

Now substituting the value of y in eq(1),

3x + 2(2) = 13

3x + 4 = 13

3x = 13-4

3x = 9

x = $\frac{9}{3}$

x =3

4 0

4 years ago

An e-commerce research company claims that 60% or more graduate students have bought merchandise on-line at their site. A consum

Rasek [7]

Answer:

We accept H₀ we don´t have enough evidence to conclude that a consumer group position is correct

Step-by-step explanation:

We have a case of test of proportion, as a consumer group is suspicious of the claim and think the proportion is lower we must develop a one tail test (left tail) Then

1.- Test hypothesis:

Null hypothesis H₀ P = P₀

Alternative hypothesis Hₐ P < P₀

2.- At significance level of α = 0,05 Critical value

z(c) = -1,64

3.-We compute z(s) value as:

z(s) = ( P - P₀ )/ √P*Q/n where P = 44/80 P = 0,55 and Q = 0,45

P₀ = 0,6 and n = 80

Plugging all these values in the equation we get:

z(s) = ( 0,55 - 0,6 ) / √(0,2475/80)

z(s) = - 0,05/ √0,0031

z(s) = - 0,05/0,056

z(s) = - 0,8928

4.-We compare z(s) and z(c)

z(s) > z(c) -0,8928 on the left side it means that z(s) is in the acceptance region so we accept H₀

7 0

3 years ago

What could be the intersection of the plane PRS and plane QRS

MrRa [10]

The plane PRS passes through the points P, R and S. So it contains the line RS. Also the plane QRS passes through the points Q, R and S. So it contains the line RS as well. Since both the planes contain the line RS, the line RS must be the intersection of plane PRS and QRS

6 0

3 years ago