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andrey2020 [161]
3 years ago
13

What is one negative angle that is co-terminal to 150°? *

Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:

-210 degrees.

Step-by-step explanation:

That is 150 - 360

= -210 degrees.

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Triangle XYZ has points X = (–4,4), Y = (0,1), and Z = (4,4). Triangle X'Y'Z' has points X ’= (–5,–4), Y’ = (–1,–1), Z’ = (3,–4)
Rama09 [41]
So they moved down one and reflected over the y axis
7 0
2 years ago
The quotient of n and -0.5 is 13. What is the value of n?
Archy [21]

Answer:

-6.5

Step-by-step explanation:

n/-0.5=13

multipy by -0.5 so

n=

-6.5

4 0
2 years ago
-2+y=9 3x-7y=3 solve the system by the substitution
kherson [118]

Hello from MrBillDoesMath!

Answer:

x = 80/3 ( 26 2/3)

y = 11


Discussion:

Step 1:

-2 + y = 9  =>                         add 2 to both sides

2 +  -2 + y = 9  +2 =>

y = 11

Step 2:

Substitute y = 11 (from Step 1) into

3x - 7y = 3  =>

3x - 7(11) = 3 =>               y = 11 from Step 1

3x - 77 = 3 =>                   add 77 to both sides

3x - 77 + 77 = 3 + 77 =>

3x = 80 =>

x = 80/3


Thank you,

MrB

3 0
3 years ago
chegg Y=4X−2 XX has a PDF of f_X(x)=\begin{cases} 3e^{-3x} & 0 \leq x \\ 0 & \text{otherwise}\end{cases}f X ​ (x)={ 3e −
Licemer1 [7]

\Bbb E[Y^2] = \Bbb E[(4X - 2)^2]

so by definition of expectation,

\Bbb E[Y^2] = \displaystyle \int_{-\infty}^\infty (4x-2)^2 f_X(x) \, dx = \int_0^\infty 3(4x-2)^2 e^{-3x} \, dx

Integrate by parts (twice).

\displaystyle \int_a^b u\,dv = uv\bigg|_a^b - \int_a^b v\,du

First, let

u = (4x-2)^2 \implies du = 8(4x-2)\,dx \\\\ dv = 3e^{-3x} \, dx \implies v = -e^{-3x}

so that

\displaystyle \Bbb E[Y^2] = -(4x-2)^2 e^{-3x} \bigg|_{x=0}^{x\to\infty} + 8 \int_0^\infty (4x-2) e^{-3x} \, dx \\\\ ~~~~ = 4 + 8 \int_0^\infty (4x-2) e^{-3x} \, dx

Next,

u = 4x-2 \implies du = 4\,dx \\\\ dv = e^{-3x} \, dx \implies v = -\dfrac13 e^{-3x}

so that

\displaystyle \Bbb E[Y^2] = 4 + 8 \left(-\frac13 (4x-2) e^{-3x} \bigg|_{x=0}^{x\to\infty} + \frac43 \int_0^\infty e^{-3x} \, dx\right) \\\\ ~~~~ = 4 + 8 \left(-\frac23 - \frac49 e^{-3x}\bigg|_{x=0}^{x\to\infty}\right) \\\\ ~~~~ = 4 - \frac{16}3 + \frac{32}9 = \boxed{\frac{20}9}

7 0
1 year ago
Finding the perimeter of each rectangle 96ft width 124ft length
dezoksy [38]

Answer:

440 ft

Step-by-step explanation:

Perimeter(p) of a rectangle is 2l + 2w

Where 'l' is the length and 'w' is the width.

p = 2(96ft) + 2(124ft) = 192 ft + 248 ft = 440 ft

5 0
2 years ago
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