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zepelin [54]
3 years ago
10

A real estate company is interested in testing whether the mean time that families in Gotham have been living in their current h

omes is less than families in Metropolis. Assume that the two population variances are equal. A random sample of 100 families from Gotham and a random sample of 150 families in Metropolis yield the following data on length of residence in current homes.
Gotham: XG = 35 months, SG2 = 900 Metropolis: XM= 50 months, SM2 = 105

Q1: Referring to Scenario 10-3, suppose ΅ = 0.10. Which of the following represents the result of the relevant hypothesis test?

A) The null hypothesis is rejected.

B)The alternative hypothesis is rejected.

C) The null hypothesis is not rejected.

D) Insufficient information exists on which to make a decision.

Q2: Referring to Scenario 10-3, suppose a = 0.10. Which of the following represents the correct conclusion?

A) There is not enough evidence that the mean amount of time families in Gotham have been living in their current homes is not less than families in Metropolis.

B)There is enough evidence that the mean amount of time families in Gotham have been living in their current homes is less than families in Metropolis.

C) There is not enough evidence that the mean amount of time families in Gotham have been living in their current homes is less than families in Metropolis.

D) There is enough evidence that the mean amount of time families in Gotham have been living in their current homes is not less than families in Metropolis.

Q3:Referring to Scenario 10-3, suppose ΅ = 0.01. Which of the following represents the correct conclusion?

A) There is not enough evidence that the mean amount of time families in Gotham have been living in their current homes is not less than families in Metropolis.

B)There is enough evidence that the mean amount of time families in Gotham have been living in their current homes is not less than families in Metropolis.

C) There is enough evidence that the mean amount of time families in Gotham have been living in their current homes is less than families in Metropolis.

D) There is not enough evidence that the mean amount of time families in Gotham have been living in their current homes is less than families in Metropolis.
Mathematics
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

the answer d , the second answer is b, the third answer is b,

Step-by-step explanation:

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3. ED = EB (given)

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Similarly consider triangles ΔABE and ΔCDE;

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2. ∠BEA = ∠DEC (vertical angles)

3. BE = DE (given)

ΔABE ≡ ΔCDE (Side-Angle-Side congruency of triangles)

∠ABE = ∠CDE and AB = CD (using CPCTC)

⇒ AB║CD (Converse of Alternate Interior angles theorem)


Since we have AB║CD, AB = CD and AD║BC, AD = BC.

Therefore, quadrilateral ABCD is a parallelogram.

****************************************************************************************************

<u>Solving Q2: The parallelogram has the angle measures shown in the diagram.</u>

It is clearly visible that both the triangles are Isosceles triangles, so opposite sides in each triangle are equal.

Consider two triangles given in the problem, we have two sets of congruent angles and one included side is common in both triangles.

Using Angle-Side-Angle congruence of triangles, both the triangles would be congruent too.

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In form ax + b = c: 2x - 8.4 = 5

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Step-by-step explanation:

4x - 8.4 = 2x + 5

2x - 8.4 = 5

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6 0
3 years ago
Insert geometric means in each geometric sequence.
Digiron [165]

Answer:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the n^{th} term of a geometric sequence.

a_n=ar^{n-1}

Where a is the first term and

r is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

ar = 24\\ar^4 = \dfrac{3}{64}

Solving the above equation:

r = \dfrac{1}{8}

Therefore, the sequence is:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

Considering the second given sequence:

ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2

Therefore, the sequence is:

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

Considering the third sequence:

a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3

Therefore, the sequence is:

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

5 0
3 years ago
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