121 is the area of the square
<span>The
population standard deviation is unknown, sample size is less than 30,
and the population has a normal or near-normal distribution</span>.
The first one would be 120 the second one would be 68
9a^2-6ab+12ac-8bc
=3a(3a-2b)+4c(3a-2b)
=(3a+4c)(3a-2b)
There you go. Have fun!
Answer:
3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x
or
x^3 + 2x^3 + 3x^6
Step-by-step explanation:
3x^4 + x^3 + 6x^2 + 2x
3x times 3x times 3x times 3x + x^3 + 6x times 6x + 2x
3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x
x^3 + 2x^3 + 3x^6
