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Mandarinka [93]
3 years ago
7

What are the next two terms after 1, 4, 6, 24, 26

Mathematics
1 answer:
vlada-n [284]3 years ago
6 0

Next two: 28 and 112

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Ill give brainliestetfgeyhe on other question too!! PLS ANSWER I CANT GO TO SUMMER SCHOOL
JulsSmile [24]

Answer:

8 grams

Step-by-step explanation:

The balance is in equilibrium, so the weights of the two sides are equal.

Let the weight of a square be s.

Left side: 2s + 4

Right side: s + 3(4) = s + 12

The weights are equal, so we set the two expressions equal.

2s + 4 = s + 12

s = 8

Answer: The weight of a square is 8 grams.

Question 2: The first step was the combine the like terms; in this example he is subtracting the 3x on both sides of the =.

8 0
3 years ago
Read 2 more answers
Make D the subject of S=D/T<br> You may use the flowchart to help you if you wish.
hammer [34]
Given the equation, S = D/T:

To make the D the subject of the equation, we can start by multiplying both sides by T to isolate D:

(T) S = D/T (T)

TS = D

Therefore, the final answer is D = TS
8 0
3 years ago
19 - |-34 - (-78)| + (-8)
enot [183]

Answer:

= -33

Step-by-step explanation:

6 0
3 years ago
Which value makes the equation true?<br><br><br><br> □+0.34=2.34
Nataly [62]

Answer:

2.00

Step-by-step explanation:

let the empty box be the variable n. n+0.34=2.34

subtract .34 from both sides

n=2.00

8 0
2 years ago
Read 2 more answers
Edg vector operations, any help appreciated!
viktelen [127]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c

____________________________________

\large \tt Solution  \: :

Vector d can be represented as :

\qquad \tt \rightarrow \:  - 2 \hat i - 2 \hat j

Vector c can be represented as :

\qquad \tt \rightarrow \:  4 \hat i + 4\hat j

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) =  - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = -  ( 4 \hat i + 4 \hat j)   - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = (-   4 \hat i  - 2 \hat  i)  + (  - 4 \hat j  - 2 \hat j)

\qquad \tt \rightarrow \: x  = - 6 \hat  i    -6 \hat j

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0
2 years ago
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