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1 year ago

PLEASE HELP WITH THIS QUESTION WILL GIVE BRAINLY

Mathematics

1 answer:

Vadim26 [7]1 year ago

8 0

Answer:

Z' = (-5,3)

Step-by-step explanation:

Move two to the (<- left) from -3,5 to get -5, 5

move two down to get -5,3

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HELP any1 good at math?

valentina_108 [34]

Step-by-step explanation:

the equations are :-

=》d = 40m + 200

=》d = 50m

here, by equalising both equations.

( since, d = d )

=》40m + 200 = 50m

=》50m - 40m = 200

=》10m = 200

=》m = 200 ÷ 10

=》m = 20

now,

=》d = 50m

=》d = 50 × 20

=》d = 1000

6 0

2 years ago

Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

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1 year ago

Nancy has 62 more erasers than Barbara. Barbara has ferasers. Write the expression that

Anna11 [10]

Answer:

F+63= The amount of erasers Nancy has

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2 years ago

Select the correct answer.

Rudiy27

Yes you are correct! :)

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2 years ago

Exits along interstate highways were formerly numbered successively from the western or southern edge of a state. However, the d

Ipatiy [6.2K]

Answer:

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