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3 years ago

5

A 4-ft vertical post casts a 12-in shadow at the same time a nearby cell phone tower casts a 118-ft shadow. How tall is the c

ell phone tower?

2 answers:

azamat3 years ago

7 0

Answer:

6 ft

Step-by-step explanation:

stiv31 [10]3 years ago

5 0

Answer:

height of vertical post = 6ft

its shadow = 20 in

For all shadows cast at the same time, the ratio of the height of a shadow-casting structure to the length of its shadow is the same. (Assuming, of course, that it's the sun casting the shadows.)

So the ratio is

4 feet / 12 inches = 4 feet / 1 foot = 4/1 = 4,

and if h is the height of the cell tower,

h/122 feet = 4

h = 4 x 122 feet = 488 feet. <---------------- Final answer

Hope I helped,

-Adrian Velez

Step-by-step explanation:

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Identify an equation in point-slope form for the line perpendicular to

Alchen [17]

Answer:

$y - 9 = \frac{1}{2}(x +3)$

Step-by-step explanation:

Given

Function; $y = -2x + 8$

Required

Find an equation perpendicular to the given function if it passes through (-3,9)

First, we need to determine the slope of: $y = -2x + 8$

The slope intercept of an equation is in form;

$y = mx + b$

<em>Where m represent the slope</em>

Comparing $y = m_1x + b$ to $y = -2x + 8$ ;

We'll have that

$m_1 = -2$

Going from there; we need to calculate the slope of the parallel line

The condition for parallel line is;

$m_1 * m_2 = -1$

Substitute $m_1 = -2$

$(-2) * m_2 = -1$

Divide both sides by -2

$m_2 =\frac{ -1}{-2}$

$m_2 =\frac{1}{2}$

The point slope form of a line is;

$y - y_1 = m_2(x - x_1)$

Where $(x_1,y_1) = (-3,9)$ and $m_2 =\frac{1}{2}$

$y - y_1 = m_2(x - x_1)$ becomes

$y - 9 = \frac{1}{2}(x - (-3))$

Open the inner bracket

$y - 9 = \frac{1}{2}(x +3)$

<em>Hence, the point slope form of the perpendicular line is: </em>

<em /> $y - 9 = \frac{1}{2}(x +3)$ <em />

3 0

4 years ago

photoshop1234 [79]

Answer:

10

Step-by-step explanation:

5/x = 4/8

Cross multiply

4*x = 5*8

4x = 40

x = 10

Answer is 10

You are correct

3 0

3 years ago

Simplify the square root of 5 times the cube root of 5.

mihalych1998 [28]

Answer:

Option 3 - five to the two thirds power

Step-by-step explanation:

Given : Expression 'the square root of 5 times the cube root of 5'.

To find : Simplify the expression ?

Solution :

Writing expression in numeric form,

The cube root of 5 means $\sqrt[3]{5}$

The square root of 5 times the cube root of 5 means $\sqrt{5\sqrt[3]{5}}$

Now, simplify the expression

$\sqrt{5\sqrt[3]{5}}=\sqrt{5\times (5)^{\frac{1}{3}}}$

$\sqrt{5\sqrt[3]{5}}=\sqrt{(5)^{1+\frac{1}{3}}}$

$\sqrt{5\sqrt[3]{5}}=\sqrt{(5)^{\frac{4}{3}}}$

$\sqrt{5\sqrt[3]{5}}=((5)^{\frac{4}{3}})^{\frac{1}{2}}$

$\sqrt{5\sqrt[3]{5}}=(5)^{\frac{4}{3}\times \frac{1}{2}}$

$\sqrt{5\sqrt[3]{5}}=(5)^{\frac{2}{3}}$

The expression is five to the two thirds power.

Therefore, Option 3 is correct.

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andre [41]

6.0 x 10^-5 I think is the answer

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Advocard [28]

Answer:

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Step-by-step explanation:

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4 years ago

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