Answer: The given logical equivalence is proved below.
Step-by-step explanation: We are given to use truth tables to show the following logical equivalence :
P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)
We know that
two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.
The truth table is as follows :
P Q ∼P ∼Q P⇔ Q ∼P ∨ Q ∼Q ∨ P (∼P ∨ Q)∧(∼Q ∨ P)
T T F F T T T T
T F F T F F T F
F T T F F T F F
F F T T T T T T
Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.
Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).
Yes so i do need to doing the times and multipics then get a fraction then u will get tot eh answer
Okay, so if e=110, then so does c, because they are Alternate Interior angles. If c=110, then so does a, because they are Alternate Exterior. Angles a and b are on a straight line, which equals 180 altogether, and 180-110 is 70, so the measure of angle b is 70.
Hope this helps ya
Answer:
Option A. 3(x+8y)
Step-by-step explanation:
