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Digiron [165]
3 years ago
7

5÷0.8= how do you solve this?

Mathematics
2 answers:
Anettt [7]3 years ago
6 0

Answer: 6.25

Step-by-step explanation: well first you gotta move a decimal over to the left once and then it'll look like this 50/8 and then solve it.

frez [133]3 years ago
5 0

Answer:6.25

Step-by-step explanation:

Grab a calculator or use one online

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“If f(x) and it’s inverse function, f^-1(x), are both plotted on the same coordinate plane, where is their point of intersection
Ghella [55]

Answer:

it is not always possible to find their intersection point for e.g take

y=x-1 it's inverse is y=x+1 so their is no intersection point but generally u find intersection points by equalizing their functions

f(x)=f^-1(x)

7 0
4 years ago
In the triangle below, what is csc E?
larisa [96]
Check the picture below.

4 0
4 years ago
86,921 in expanded form
Rudik [331]
86921 = 80000 + 6000 + 900 +20 +1
3 0
3 years ago
Read 2 more answers
Test pls help! thank you​
natita [175]

Answer:

The Answer is 5/12

Pls mark as brainliest

5 0
3 years ago
Read 2 more answers
How do you do this question?
Alex Ar [27]

Step-by-step explanation:

(a) dP/dt = kP (1 − P/L)

L is the carrying capacity (20 billion = 20,000 million).

Since P₀ is small compared to L, we can approximate the initial rate as:

(dP/dt)₀ ≈ kP₀

Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.

20 = k (6,100)

k = 1/305

dP/dt = 1/305 P (1 − (P/20,000))

(b) P(t) = 20,000 / (1 + Ce^(-t/305))

6,100 = 20,000 / (1 + C)

C = 2.279

P(t) = 20,000 / (1 + 2.279e^(-t/305))

P(10) = 20,000 / (1 + 2.279e^(-10/305))

P(10) = 6240 million

P(10) = 6.24 billion

This is less than the actual population of 6.9 billion.

(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))

P(100) = 7570 million = 7.57 billion

P(600) = 20,000 / (1 + 2.279e^(-600/305))

P(600) = 15170 million = 15.17 billion

7 0
3 years ago
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