One way to carry out this problem is to simply take the value that you already know, which is that 1/5 is 20 % and multiply it by 2 for 2/5 or 2 (1/5ths) and do this for all of them. There is a pattern that occurs for every increase in one out of denominator of 5.
Answer:
Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft
Step-by-step explanation:
Amount of sausage links made on Friday morning = 8 ft
Amount of sausage links used on Friday night = 4 ft
Amount of sausage links remaining = 8 - 4 = 4ft (i)
Amount of sausage links made on Saturday morning = 8 ft (ii)
So,
Total amount of sausage links = 8 + 4 = 12 ft (from (i) and (ii) )
Amount of sausage links used on Saturday night = 12 ft
Amount of sausage links remaining = 12 - 12 = 0 ft
Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft
Answer:
1/2(bh)
A=20
Step-by-step explanation:
Answer:
99
Step-by-step explanation:
The distance between 0 and 99 is 99
Answer:
~ 83.90
2 decimal place is basically the hundredths place
