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neonofarm [45]
3 years ago
6

Not providing guarding or fall protection for workers on a 25-foot scaffold. The resulting fall would most likely end in death,

broken bones, and/or other serious injuries. What violation type does this describe?
Computers and Technology
1 answer:
OlgaM077 [116]3 years ago
4 0
<span>Not providing any fall protection on scaffolding would mean be a work hazard and a workplace safety violation und the Occupational and Safety Health Act. The employer would be punishable for this offence. He is required to provide necessary safety measures for his employees.</span>
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Elena L [17]

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Which type of connection is needed to synchronize data with a cloud service?
Svetllana [295]

Answer:

Internet

Explanation:

The "Cloud" is an Online service this means it works on the Internet and without the Internet you can't have access to it.

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A physical cpu core without hyper-threading enabled can process two instructions at the same time.
diamong [38]

A physical CPU core without hyper-threading enabled can process two instructions at the same time is a false statement.

<h3>Can a CPU do multiple things at once?</h3>

Computers are those that do only one task (or process) at a single time. But a computer can alter tasks very fast and can do a lot of work.

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2 years ago
HIPAA protects which of the following kinds of data?
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5 0
3 years ago
Read 2 more answers
Write a program that first gets a list of integers from input. Then, get another value from the input, and output all integers l
jonny [76]

Answer:

The c++ program for the given scenario is given below.

#include <iostream>

using namespace std;

int main() {

   int len=20, arr[len], data;    

   // initialize all elements of the array to 0

   for(int i=0; i<len; i++)

   {

       arr[i] = 0;

   }    

   cout<<"This program outputs all the numbers less than or equal to the given number."<<endl;

   cout<<"Enter the list of numbers. Enter 0 to stop entering the numbers. "<<endl;

   for(int i=0; i<len; i++)

   {

       cin>>arr[i];        

       // 0 indicates user wishes to stop entering values  

       if(arr[i] == 0)

           break;

       else

           continue;

   }    

   // number from which the list is to be compared

   cout<<"Enter the number to be compared."<<endl;

   cin>>data;

     

   cout<<"The values less than or equal to the number "<<data<<" are "<<endl;

   for(int i=0; i<len; i++)

   {  

       // 0 indicates the end of the list entered by the user

       if(arr[i]==0)

           break;

       if(arr[i] <= data)

           cout<<arr[i]<<endl;

   }    

   return 0;    

}  

OUTPUT

This program outputs all the numbers less than or equal to the given number.

Enter the list of numbers. Enter 0 to stop entering the numbers.  

23

45

67

89

10

0

Enter the number to be compared.

59

The values less than or equal to the number 59 are  

23

45

10

Explanation:

This program takes input only from the user and makes no assumptions.

The list of numbers entered by the user are stored in an array. If the user input is less than the size of the array, the remaining elements are set to 0.

While taking input from the user, if any element of the array is found to be 0, the loop is discontinued.

for(int i=0; i<len; i++)

   {

       cin>>arr[i];        

       if(arr[i] == 0)

           break;

       else

           continue;

   }  

Same test is applied when all the numbers less than the given number are displayed.

for(int i=0; i<len; i++)

   {  

        if(arr[i]==0)

           break;

       if(arr[i] <= data)

           cout<<arr[i]<<endl;

   }

The above program takes into account all the specifications in the given question.

5 0
3 years ago
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