Question

Anybody know the answer??

Answer 1

That's a factored equation set to zero, so either of the factors may be zero

$\cot \theta + 1 = 0$

$\cot \theta = -1$

$\tan \theta = \dfrac{1}{-1} = -1$

Slope of -1 in the first two quadrants is 135° aka

$\theta = \dfrac{3 \pi}{4}$

Let's look at the other factor.

$\sec \theta - \frac 1 2 = 0$

$\sec \theta = \frac 1 2$

$\cos \theta = 2$

That has no solutions so we're left with our answer:

Answer: 3π / 4

Answer 2

If you solve for theta, it would be 3pi/4