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ale4655 [162]
2 years ago
5

What is another name for Angle 2? Lines E H and D F intersect at point G. Angle 2 is formed by line segments D G and G E and ang

le 1 is formed by line segments E G and G F. Angle D G E Angle G E D Angle E G F Angle G E F
Mathematics
1 answer:
astraxan [27]2 years ago
8 0

When two straight lines or rays intersect at a shared endpoint, an angle is generated. The correct option is A.

<h3>What is an angle?</h3>

When two straight lines or rays intersect at a shared endpoint, an angle is generated. An angle's vertex is the common point of contact. Angle is derived from the Latin word angulus, which means "corner."

The diagram for the given problem can be made as shown below. Therefore, the other name for angle 2 will be ∠DGE.

Hence, the correct option is A.

Learn more about Angle:

brainly.com/question/7116550

#SPJ1

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Mnenie [13.5K]
19975 is your answer hopefully this helps!
3 0
3 years ago
Yumi and Juan pick up litter along the highway at the same rate. Yumi picks up litter for 3 miles and takes two hours longer tha
oksano4ka [1.4K]
Juan's time = x
Yumi's time = x + 2
Yumi's distance = 3 miles
Juan's distance = 2 miles
Rate = distance/time
Juan's rate = 2/x
Yumi's rate = 3/(x + 2)
The rates are equal so:
2/x = 3/(x + 2)
2x + 4 = 3x
x = 4 hours
Yumi's time = 4 + 2 = 6 hours
The answer is D.
3 0
3 years ago
Read 2 more answers
Which of the following expressions represents the least common multiple of 15, 18, and 25?
Virty [35]

Answer:

(2)(3^2)(5^2)

Step-by-step explanation:

we know that

The <u>Least Common Multiple</u> (LCM) of a group of numbers is the smallest number that is a multiple of all the numbers.

we have

15,18 and 25

Decompose the numbers in prime factors

15=(3)(5)

18=(2)(3^2)

25=(5^2)

Multiply common and uncommon numbers with their greatest exponent

so

The LCM is equal to

LCM=(2)(3^2)(5^2)

LCM=450

7 0
3 years ago
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
How to find the area of a tilted square?
Katena32 [7]
A square has 4 sides of equal legnths
in your point of view, it looks tilted because it is actually a rhombus, a paralellogram (4 sided figure with 2 pairs of paralell sides) with 4 equal sides

to find the area, just multiply  base by height (look at ilustration/attachmtns)

3 0
3 years ago
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