For the given sample, mean = 1.307 and standard deviation = 0.1865.
Given,
Sample
xi : 0.96, 1.40, 1.57, 1.25, 1.16, 1.46, 1.44, 1.50, 1.11, 1.22
Total samples N=10
Mean,
(∑
) / N
= (0.96 + 1.40 + 1.57 + 1.25 + 1.16 + 1.46 + 1.44 + 1.50 + 1.11 + 1.22) / 10
= 13.07/10
= 1.307
Standard deviation =((∑
/N)
Therefore we have to calculate (∑ first.
That is,
(∑
= (0.96 - 1.307)² + (1.40 - 1.307)² + (1.57 - 1.307)² + (1.25 - 1.307)² + (1.16 - 1.307)² + (1.46 - 1.307)² + (1.44 - 1.307)² + (1.50 - 1.307)² + (1.11 - 1.307)² + (1.22 - 1.307)²
= 0.34781
Now standard deviation = √((∑/N)
=
= 0.1865
Therefore, for the given sample, mean = 1.307 and standard deviation = 0.1865.
Learn more about sample here: brainly.com/question/28443861
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