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Allushta [10]
3 years ago
8

Guyyysss.. :) Help me solve this geometry problem

Mathematics
1 answer:
Lerok [7]3 years ago
8 0

Answer:

The question asks arc length:

\frac{ \frac{ \frac{2\pi}{3} }{2\pi} }{1}  =  \frac{1}{3}

Dividing by

2\pi

Because 360°(by formula)

Therefore:

\frac{1}{3}  \times  \frac{2\pi \times 8}{1}  =  \frac{16\pi}{3 }  = 5 \ \frac{\pi}{3}  \\ so \: arc \: length \: =  \frac{16\pi}{3}

Good luck!

Intelligent Muslim,

From Uzbekistan.

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Answer:

a) r=-0.719

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Step-by-step explanation:

a)

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The correlation coefficient is computed by following formula

r=\frac{nsumxy-(sumx)(sumy)}{\sqrt{[nsumx^{2} -(sumx)^2][nsumy^2-(sumy)^2]}}

r=\frac{4(92)-(18)(25)}{\sqrt{[4(102) -(18)^2][4(195)-(25)^2]}}

r=\frac{368-450}{\sqrt{[408 -324][780-625]}}

r=\frac{-82}{\sqrt{[84][155]}}

r=\frac{-82}{\sqrt{13020}}\\r=\frac{-82}{114.1052}\\r=-0.7186

By rounding r to 3 decimal places we get r=-0.719.

b)

The regression equation can be written as y=a+bx

We have to find "a" and "b" for regression equation

b=\frac{nsumxy-(sumx)(sumy)}{{nsumx^{2} -(sumx)^2}}

a=ybar-b(xbar)

b=\frac{4(92)-(18)(25)}{{4(102) -(18)^2}}

b=\frac{-82}{{84}}

b=-0.976

xbar=sumx/n

xbar=18/4=4.5

ybar=sumy/n

ybar=25/4=6.25

a=ybar-b(xbar)

a=6.25-(-0.976)4.5

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a=10.642

Thus, the regression equation is

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The predicted value of y for x=3 can be computed by putting the value of x in regression equation

y=10.642-0.976(3)

y=10.642-2.928

y=7.714

Hence, the predicted y-value for x=3 is 7.714.

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